4/7. Isgreater because the smaller the fraction the more its worth
Answer:

Step-by-step explanation:
= Area of 1st rectangle = 
= Area of 2nd rectangle = 


The number of pounds required for the counter top is


The required expression is
.
Answer:
The sample mean will approach 76
Step-by-step explanation:
Refer to Law of large numbers (LLN) and the central limit theorem (CLT)
For random sample, with sample size n, in population with expected value μ, the sample mean converge almost surely to the expected value μ as n -> ∞
Answer:
Domain: -3 ≤ x ≤ 9
Step-by-step explanation:
The domain of the graph is the set of all possible x-values.
The set of all possible values as represented on the graph above runs from -3 to 9.
This, domain of the graph is -3 ≤ x ≤ 9
Answer:
<h3>#1</h3>
The normal overlaps with the diameter, so it passes through the center.
<u>Let's find the center of the circle:</u>
- x² + y² + 2gx + 2fy + c = 0
- (x + g)² + (y + f)² = c + g² + f²
<u>The center is:</u>
<u>Since the line passes through (-g, -f) the equation of the line becomes:</u>
- p(-g) + p(-f) + r = 0
- r = p(g + f)
This is the required condition
<h3>#2</h3>
Rewrite equations and find centers and radius of both circles.
<u>Circle 1</u>
- x² + y² + 2ax + c² = 0
- (x + a)² + y² = a² - c²
- The center is (-a, 0) and radius is √(a² - c²)
<u>Circle 2</u>
- x² + y² + 2by + c² = 0
- x² + (y + b)² = b² - c²
- The center is (0, -b) and radius is √(b² - c²)
<u>The distance between two centers is same as sum of the radius of them:</u>
<u>Sum of radiuses:</u>
<u>Since they are same we have:</u>
- √(a² + b²) = √(a² - c²) + √(b² - c²)
<u>Square both sides:</u>
- a² + b² = a² - c² + b² - c² + 2√(a² - c²)(b² - c²)
- 2c² = 2√(a² - c²)(b² - c²)
<u>Square both sides:</u>
- c⁴ = (a² - c²)(b² - c²)
- c⁴ = a²b² - a²c² - b²c² + c⁴
- a²c² + b²c² = a²b²
<u>Divide both sides by a²b²c²:</u>
Proved