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Dmitriy789 [7]
3 years ago
12

One pound of grout is enough to grout a tiled area that is 110 sq. Ft. Alyssa's kitchen counter is made up of two rectangular se

gments. One is 10.3 ft by 2.5 ft, and the other is 3.1 ft by 2 ft. Which expression represents the number of pounds of grout Alyssa will need? (Hint: Area 1st Rectangle = (10.3)(2.5); Area 2nd Rectangle = (3.1)(2); Total Area = Area 1st + 2nd) 10.3(2.5) + (3.1(2) ÷ 110) 10.3(2.5) + 3.1(2) ÷ 110 (10.3 (2.5) + 3.1 (2)) ÷ 110 3.1(2) + (10.3)(2.5) ÷ 110
Mathematics
2 answers:
Ratling [72]3 years ago
6 0

Answer:

(10.3(2.5)+3.1(2))\div 110

Step-by-step explanation:

A_1 = Area of 1st rectangle = (10.3\times 2.5)\ \text{ft}^2

A_2 = Area of 2nd rectangle = (3.1\times 2)\ \text{ft}^2

1\ \text{pound of grout}=110\ \text{ft}^2

\Rightarrow 1\ \text{ft}^2=\dfrac{1}{110}\ \text{pound of grout}

The number of pounds required for the counter top is

\text{Total area}\times \text{The amount of grout used in 1 ft}^2

=A_1+A_2\times \dfrac{1}{110}=(10.3(2.5)+3.1(2))\times \dfrac{1}{110}\\ =(10.3(2.5)+3.1(2))\div 110

The required expression is (10.3(2.5)+3.1(2))\div 110.

anyanavicka [17]3 years ago
3 0

Answer:

The answer is C

Step-by-step explanation:

I just got it correct on edg

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Find the total surface area of the<br> following square pyramid:<br> 9 cm<br> 10 cm<br> SA = [?]cm2
MakcuM [25]

Answer:

280 cm2

Step-by-step explanation:

1)find the area of square

A=LW

=10×10

=100

2) find the area of triangle

A=B×H÷2

=10×9/2

=45

Coz,there are 4 triangle we multiple by 4

=45×4

=180

3)find the total surface area by adding the two

=100+180

=280cm2

4 0
3 years ago
Angles on a Straight line always add up to........... degrees
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Answer:

180°

Step-by-step explanation:

Angles that are called straight angles make up a straight line.

A straight line measures 180°.

So, angles on a straight line make up 180°.

Hope this helps.

4 0
3 years ago
Could you help me. ​
Sedbober [7]

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X-Large

Step-by-step explanation:

8 0
3 years ago
Helllppppp can’t find the answer!!!
alukav5142 [94]
Slope of a line can be determined using this formula
m = (y₂ - y₁) / (x₂ - x₁)

From the question, we know that
(x₁,y₁) = (2,-3)
(x₂,y₂) = (2,9)

plug the numbers into the formula
m = (y₂ - y₁) / (x₂ - x₁)
m = (9 - (-3)) / (2 - 2)
m = (9 + 3) / (2 - 2)
m = 12/0
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The pairs must form a vertical line
8 0
3 years ago
On a cold day, hailstones fall with a velocity of 2i − 6k m s−1 . If a cyclist travels through the hail at 10i m s−1 , what is t
Paraphin [41]

Answer:

The velocity of the hail relative to the cyclist is V_{hc}=-8\hat{i}-6\hat{k}

The angle at which hailstones falling relative to the cyclist is \theta = 36.86^\circ

Step-by-step explanation:

Given : On a cold day, hailstones fall with a velocity of 2\hat{i}-6\hat{k}\text{ m/s} . If a cyclist travels through the hail at 10\hat{i} \text{ m/s}.

To find : What is the velocity of the hail relative to the cyclist and At what angle are the hailstones falling relative to the cyclist?

Solution :

The velocity of the hailstone falls is V_h=2\hat{i}-6\hat{k}\text{ m/s}

The velocity of the cyclist travels through the hail is V_c=10\hat{i} \text{ m/s}

The velocity of the hail relative to the cyclist is given by,

V_{hc}=V_h-V_c

Substitute the value in the formula,

V_{hc}=2\hat{i}-6\hat{k}-10\hat{i}

V_{hc}=-8\hat{i}-6\hat{k}

So, The velocity of the hail relative to the cyclist is V_{hc}=-8\hat{i}-6\hat{k}

Now, The angle of hails falling relative to the cyclist is given by

\theta = \tan^{-1}(\frac{-6}{-8})

\theta = \tan^{-1}(\frac{3}{4})

\theta = 36.86^\circ

So, The angle at which hailstones falling relative to the cyclist is  \theta = 36.86^\circ

4 0
3 years ago
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