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k0ka [10]
2 years ago
15

Marsha sees an airplane flying overhead. The spot on the ground that is directly under the plane is 3,600 feet from Marsha's hou

se. She sees the plane at a 45o angle of elevation. What is the elevation of the plane?

Mathematics
1 answer:
Rudiy272 years ago
7 0

The elevation of the plane is 3600 ft

Let

  • h = elevation of plane,
  • d = distance from Marsha's house to spot on ground below plane = 3600 feet and
  • Ф = angle of elevation of plane = 45°

From the triangle, we have the trigonometric ratio

tanФ = h/D

<h3>Elevation of the plane</h3>

Making h subject of the formula, we have

h = DtanФ

substituting the values of the variables into the equation, we have

h = DtanФ

h = 3600 ft × tan45°

h = 3600 ft × 1

h = 3600 ft

So, the elevation of the plane is 3600 ft

Learn more about elevation of the plane here:

brainly.com/question/26380084

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deposit

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3. Sam and Tim each have savings accounts. Every month they each put in some of their
Setler [38]

Answer:

y = 30x +50 --- Sam

y = 20x +80 --- Tim

Step-by-step explanation:

Given

Sam                         Tim

х  --- f(x) ---------------  g(x)

1  --- 80   --------------- 100

2  --- 110  --------------- 120

3  --- 140 --------------- 140

4 --- 170 -------------- 160

Required

Determine the y value

y value implies the equation of the table

Calculating the equation of Sam

First, we need to take any corresponding values of x and y

(x_1,y_1) = (1,80)

(x_2,y_2) = (4,170)

Next, we calculate the slope (m)

m = \frac{y_2 - y_1}{x_2 - x_1}

m = \frac{170 - 80}{4 - 1}

m = \frac{90}{3}

m = 30

Next, we calculate the line equation using:

y - y_1=m(x-x_1)

y - 80 = 30(x - 1)

y - 80 = 30x - 30

Make y the subject

y = 30x - 30 + 80

y = 30x +50

Calculating the equation of Tim

First, we need to take any corresponding values of x and y

(x_1,y_1) = (1,100)

(x_2,y_2) = (4,160)

Next, we calculate the slope (m)

m = \frac{y_2 - y_1}{x_2 - x_1}

m = \frac{160 - 100}{4 - 1}

m = \frac{60}{3}

m = 20

Next, we calculate the line equation using:

y - y_1=m(x-x_1)

y - 100 = 20(x - 1)

y - 100 = 20x - 20

Make y the subject

y = 20x - 20+100

y = 20x +80

7 0
3 years ago
Quadrilateral ABCD?<br>​
Mashutka [201]

The given quadrilateral is a kite.

Given: Point A (2, 4), B (-2, -5), C (7, -1) and D (7, 4)

Firstly, we find the distance between AD and DC

AD = \sqrt{(7 - 2)^{2} + (4 - 4)^{2}  }

⇒ AD = \sqrt{5^{2} }

⇒ AD = 5

DC = \sqrt{(7 - 7)^{2} + (4 - (-1))^{2} }

⇒ DC = \sqrt{5^{2} }

⇒ DC = 5

Hence, AD = DC = 5

Now, find the distance between AB and BC

AB = \sqrt{(-2 - 2)^{2}  + (-5 - 4)^{2} }

⇒ AB = \sqrt{(-4)^{2} + (-9)^{2}  }

⇒ AB = \sqrt{16 + 81}

⇒ AB = \sqrt{97}

BC = \sqrt{(7 - (-2))^{2} + (-1 - (-5))^{2}  }

⇒ BC = \sqrt{9^{2}  + 4^{2} }

⇒ BC = \sqrt{81 + 16}

⇒ BC = \sqrt{97}

Hence, AB = BC = √97

In the given quadrilateral, the two pair is of equal length and these sides are adjacent to each other.

Hence, it follows the property of kite.

For more questions on quadrilateral, visit:

brainly.com/question/23935806

#SPJ9

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I need to find the product of f and g. what is the domain and range of the product
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Step-by-step explanation:

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By looking at the graph, we can tell that f(x) is a quadratic function because of the symmetry. We can also tell that it never goes below 4. Knowing this, we can determine the domain and range.

Domain: {x | all real numbers}

Range: {y | y > 4}

By looking at the graph, we can tell that g(x) is an exponential function because it has a curve, and never goes below the x. Knowing this, we can determine the domain and range.

Domain: {x | all real numbers}

Range: {y | y > 0}

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Can someone please help me with my homework <br> Ignore the bottom question
pav-90 [236]

1. x = 1    2. x = -30   3. x = -2   4. x = 15   5. x = 7, y = 11   6. x = 4, y = 1  

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6 0
3 years ago
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