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DIA [1.3K]
4 years ago
13

THE AP CALCULUS EXAM SCORES WERE RELEASED IN JULY. THE SECONDARY MATH SPECIALIST PREPARED THE BOX PLOT SHOWN TO PRESENT THE SCOR

ES TO THE SUPERINTENDENT. WHAT'S THE RANGE OF SCORES THAT REPRESENTS THE MIDDLE 50 PERCENT OF THE STUDENTS WHO TOOK THE TEST?
    
  A. 65%–89%
  B. 65%–94%
  C. 81%–89%
  D. 65%–81%

Mathematics
1 answer:
Ganezh [65]4 years ago
8 0

Answer : option A

To find the range of scores that represents the middle 50 % of the student who took the test , we find inter quartile

Inter quartile range is the middle 50% of the given range of scores.

The difference between the upper quartile and lower quartile is the inter quartile that is middle 50%

From the diagram , we can see that

Upper quartile = 89

lower quartile = 65

So range is 65%  to 89%

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The diagram below shows the contents of a jar from which you select marbles at random.
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3 years ago
Solve y-12/25=3 1/5. What number is y?<br><br> A. 3 1/5<br> B. 3 17/25<br> C. 3 7/25<br> D. 4 17/25
kicyunya [14]

Answer:

Option c) y=3\frac{17}{25} is correct

The value of y is 3\frac{17}{25}

Step-by-step explanation:

Given equation is  

y-\frac{12}{25}=3\frac{1}{5}

To solve the given equation for y

y-\frac{12}{25}=3\frac{1}{5}

y-\frac{12}{25}=\frac{16}{5}  (converting mixed fraction to normal fraction )

y-\frac{16}{5}=\frac{12}{25}

y-\frac{(16\times 5)+12}{25}  (taking LCM 25 )

=\frac{80+12}{25}  (adding the terms )

y=\frac{92}{25}  (now convert fraction into mixed fraction )

Therefore y=3\frac{17}{25}

Option c) y=3\frac{17}{25} is correct

The value of y is 3\frac{17}{25}

6 0
3 years ago
In a factory, 3.25% of the jars of peanut butter produced contains less peanut butter than is advertised on the label. The facto
marshall27 [118]

Answer:

936 jars of peanut butter contain less peanut butter than usual.

Step-by-step explanation:

1. First, we need to find how many jars of peanut butter that contain less peanut butter than advertised are produced every hour.

The factory produces 1200 jars of peanut butter every hour

3.25% of those jars have less peanut butter than advertised

So: multiply (1200*.0325) (the decimal form of the percent) to find the amount of peanut butter jars that contain less peanut butter than advertised.

(1200*.0325) = 39

So the factory produces 39 jars of peanut butter that contain less peanut butter than advertised.

2. Second, we need to find how many jars of peanut butter that contain less peanut butter than advertised in three 8 hour work days.

Lets add these work days together to find the total amount of hours: (8 + 8 + 8) = 24

So: three 8 hour work days totals to 24 hours

Since the factory produces 39 jars of peanut butter that contain less peanut butter than advertised per hour. Multiply (24 * 39) to find the total amount of jars produced in three 8 hour work days.

(24 *39) = 936

A total of 936 peanut butter jars are produced in three 8 hour work days that contain less peanut butter than advertised.

3. If you want to double check your work do the following.

Since the factory produces 1200 jars an hour and 24 hours total three 8 hour work days. Multiply (1200*24) = 28800

So there is a total of 28800 jars produced in three 8 hour work days.

Then you can multiply 28800 by 3.25% of jars that contain less peanut butter to find the total amount of peanut butter jars that contain less peanut butter in three 8 hour work days.

(28800 * .0325) = 936

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