The roots of an equation are simply the x-intercepts of the equation.
See below for the proof that
has at least two real roots
The equation is given as: 
There are several ways to show that an equation has real roots, one of these ways is by using graphs.
See attachment for the graph of 
Next, we count the x-intercepts of the graph (i.e. the points where the equation crosses the x-axis)
From the attached graph, we can see that
crosses the x-axis at approximately <em>-2000 and 2000 </em>between the domain -2500 and 2500
This means that
has at least two real roots
Read more about roots of an equation at:
brainly.com/question/12912962
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Answer:
Perimeter = Side1 + Side2 + Side3
4x + 3y = 5x - 3y + x + 4y + Side3
4x + 3y = 6x + y + Side3
-2x + 2y = y + Side3
Step-by-step explanation:
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Answer:
Option c) is correct.
The value of y in the given equation is 26 ie., y=26
Step-by-step explanation:
Given equation is

Now to the find the value of y in the above equation.
To find y simplify the above equation


Now apply distributive property



Therefore y=26
Option c) is correct.
The value of y in the given equation is 26 ie., y=26