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Rasek [7]
3 years ago
7

Plz help me ...

Mathematics
1 answer:
Novay_Z [31]3 years ago
8 0
  • 10kg=390 Rs
  • 100kg=4 000 Rs
  • 390x10= 3900 rs
  • 4000-3900=100 Rs
  • lỗ 100rs
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Faces, edges and corners of star<br> pls fast <br><br><br><br> thankyou
aleksklad [387]

Answer:

I don't understand what your asking us to do.

Step-by-step explanation:

Can you rephrase it please.

3 0
3 years ago
What are the domain and range of g of x equals negative 3 times the square root of the quantity x minus 1? d: (1, [infinity]) an
leonid [27]
The domain of it is d: [1,+infinity) and the range is r: (-infinity,0].
3 0
1 year ago
Enrique and Yolanda collected 500 pieces of candy on Halloween. They gave half of their candy to charity. Yolanda took 180 piece
777dan777 [17]
The answer would be C. (He counted Yolanda's candy as his own).

This is found by multiplying 500 (starting number of candy) and .64 (percentage divided by a hundred). Thjs would guve you 320, which you would then subtract from the starting number of candy (500) to get 180. 180 is Yolanda's number of candy, which gives you the answer.
4 0
3 years ago
Solve the following differential equations or initial value problems. In part (a), leave your answer in implicit form. For parts
shepuryov [24]

Answer:

(a) (y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) y = arctan(t(lnt - 1) + C)

(c) y = -1/ln|0.09(t + 1)²/t|

Step-by-step explanation:

(a) dy/dt = (t^2 + 7)/(y^4 - 4y^3)

Separate the variables

(y^4 - 4y^3)dy = (t^2 + 7)dt

Integrate both sides

(y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) dy/dt = (cos²y)lnt

Separate the variables

dy/cos²y = lnt dt

Integrate both sides

tany = t(lnt - 1) + C

y = arctan(t(lnt - 1) + C)

(c) (t² + t) dy/dt + y² = ty², y(1) = -1

(t² + t) dy/dt = ty² - y²

(t² + t) dy/dt = y²(t - 1)

(t² + t)/(t - 1)dy/dt = y²

Separating the variables

(t - 1)dt/(t² + t) = dy/y²

tdt/(t² + t) - dt/(t² + t) = dy/y²

dt/(t + 1) - dt/(t(t + 1)) = dy/y²

dt/(t + 1) - dt/t + dt/(t + 1) = dy/y²

Integrate both sides

ln(t + 1) - lnt + ln(t + 1) + lnC = -1/y

2ln(t + 1) - lnt + lnC = -1/y

ln|C(t + 1)²/t| = -1/y

y = -1/ln|C(t + 1)²/t|

Apply y(1) = -1

-1 = ln|C(1 + 1)²/1|

-1 = ln(4C)

4C = e^(-1)

C = (1/4)e^(-1) ≈ 0.09

y = -1/ln|0.09(t + 1)²/t|

8 0
3 years ago
The diagonal of a rectangle is 25 in. The width is 15 in. What is the area of the rectangle?
Nana76 [90]

Answer:

375 in² is the answer.

Step-by-step explanation:

Are of rectangle= area of 2 triangle

= 1/2*25*15+1/2*25*15

=187.5+187.5

=375 in²

7 0
2 years ago
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