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Rasek [7]
3 years ago
7

Plz help me ...

Mathematics
1 answer:
Novay_Z [31]3 years ago
8 0
  • 10kg=390 Rs
  • 100kg=4 000 Rs
  • 390x10= 3900 rs
  • 4000-3900=100 Rs
  • lỗ 100rs
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Find the average rate of change from interval x=-1 to x=2
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Step-by-step explanation:

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1. What is the solution of n² – 49 = 0? (1 point)
maks197457 [2]

Answer:

1. n=\pm7

2. x=\pm7i[tex]3.[tex]\pm 12x =a

4. 22

Step-by-step explanation:

1. n^2 - 49 = 0

n^2 =49

n= \sqrt{49}

n=\pm7

2. x^2+64 = 0

x^2 =-64

x= \sqrt{49}

x=\pm7i[tex]3. Area of square = [tex]a^{2}

Where a is the side

We are given an area o square = 144x^{2}

So, 144x^{2}=a^{2}

\sqrt{144x^{2}}=a

\pm 12x =a

4. We are given that the solution of quadratic equation -9 and 9

So, equation becomes:

(x+9)(x-9)=0

x^2- 81=0

So, in the given equation x^2 + z = 103

z should be the number from which if we subtract 103 so we get 81

Substitute z = 22

x^2 + 22 = 103

x^2 + 22 -103=0

x^2 -81=0

Thus the value of z is 22

8 0
3 years ago
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