If

, then
![\sqrt[2]{y}=\sqrt[2]{x^2}=x](https://tex.z-dn.net/?f=%5Csqrt%5B2%5D%7By%7D%3D%5Csqrt%5B2%5D%7Bx%5E2%7D%3Dx)
if

, then
![\sqrt[3]{y}=\sqrt[3]{x^3}=x](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7By%7D%3D%5Csqrt%5B3%5D%7Bx%5E3%7D%3Dx)
ok

so
![\sqrt[2]{64}=\sqrt[2]{8^2}=8](https://tex.z-dn.net/?f=%5Csqrt%5B2%5D%7B64%7D%3D%5Csqrt%5B2%5D%7B8%5E2%7D%3D8)
![\sqrt[3]{64}=\sqrt[3]{4^3}=4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64%7D%3D%5Csqrt%5B3%5D%7B4%5E3%7D%3D4)
well, the cube root usually bigger
The way I solved this problem was by subtracting 200-75 and getting 125. So he would need to mow 125 more lawns. To check your answer you can add 125+75 and get 200
I hope this helped :)
This is true. To find the circumference (the distance around the circle) you multiply the diameter with pi.
Answer:
The mean is 21.62 which is approximately 22
Step-by-step explanation:
mean= 15+20+10+12+20+16+80+18/8=21.62 because
mean= sum of all numbers/numbers mentioned
Answer:
Part 1) Option A. h(2) = 86.00 means that after 2 seconds, the height of the ball is 86.00 ft
Step-by-step explanation:
we have

where
t ----> is the time in seconds after the ball is dropped
h(t) ----> he height in feet of a ball dropped from a 150 ft
Find h(2)
That means ----> Is the height of the ball 2 seconds after the ball is dropped
Substitute the value of t=2 sec in the equation

therefore
After 2 seconds, the height of the ball is 86.00 ft.