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tankabanditka [31]
3 years ago
10

A school has 800 students. Every Wednesday, 12 percent of the students stay after school fo Chess Club. How many students attend

Chess Club?
Mathematics
1 answer:
notsponge [240]3 years ago
3 0
For this we just want to set it to a proportion so I hope this helps!

\frac{x}{800} =  \frac{12}{100}

From there, cross multiply, therefore 800 by 12 and 100 by x.

9600 = 100x

Divide\;both\;sides\;by\;100\ \textgreater \   \frac{9600}{100} =  \frac{100x}{100}  \ \textgreater \  96

Therefore 96 students attended the Chess Club.

Hope this helps!
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Hardy's plant grows rapidly. It grows by 10cm every 2 years. How much taller will Hardy's plant be in 5 years?
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The midpoint of UV is (5, -10). The coordinates of one endpoint are U(3,6). Find the coordinates of endpoint V.
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The answer is (7, -26) for The second endpoint.  

We'll call the midpoint M. In order to find this, we must first note that to find a midpoint we need to take the average of the endpoints. To do this we add them together and then divide by 2. So, using that, we can write a formula and solve for each part of the k coordinates. We'll start with just x values.

(Ux + Vx)/2 = Mx

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And now we do the same thing for y values

(Uy + Vy)/2 = My

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This gives us the final point of (7, -26)

6 0
3 years ago
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[PLEASE ANSWER BOTH QUESTIONS] The following data points represent the number of quesadillas each person at Toby's Tacos ate. So
Fynjy0 [20]

Answer:

Part 1: Already solved.

Part 2: 1 quesadilla.

Step-by-step explanation:

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The data are already sorted from least to greatest.

Part 2: To get the interquartile range, we must know the first and third quartiles. To find those, we need to know the median of the data.

There are 11 data points, so we can cross out 5 numbers on the left and cross out 5 numbers on the right. That leaves a median of 1.

Since we know the median is 1, we can find the first quartile by finding the median of the following numbers: 0, 0, 1/4, 1/2, 1/2 (any number less than 1). There are five numbers, so cross out two numbers from the left and cross out two numbers from the right. We are left with a first quartile of 1/4.

Now that we have the first quartile, we need to find the third quartile. Since the median was actually the first "1" in the data set, the third quartile will be the median of the numbers to the right of that "1": 1, 1, 5/4, 2, 2. Cross out the leftmost two numbers, and cross out the rightmost two numbers. We are left with a third quartile of 5/4.

Now that we have both the third and first quartiles, we can find the interquartile range! The IQR is calculated by finding the third quartile minus the first quartile. 5/4 - 1/4 = 4/4 = 1.

So, your interquartile range is 1 quesadilla.

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5 0
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