Calculate the probability that both bids are successful
Answer:
The probability that both contracs are successful is 0.21
Step-by-step explanation:
Given
E1 = the event that the bid on the first contract is successful
E2 = the event that the bid on the second contract is successful
P(E1) = 0.3
P(E2) = 0.7
Let P(A) represent the event that both contracts are successful
P(A) = P(E1 and E2)
Since both events are independent. P(A) becomes
P(A) = = P(E1 * P(E2)
By substituton
P(A) = 0.3 * 0.7
P(A) = 0.21
Hence the probability that both contracs are successful is 0.21
Answer: The equation that represents the road is y= - 1/3x +1/3
Step-by-step explanation:
Answer:
The smaller number equals 12, the larger number equals 51.
Step-by-step explanation:
x + (3x + 15) = 63
Combine like terms.
4x + 15 = 63
Subtract 15 from both sides.
4x + (15 -15) = (63 - 15)
4x = 48
Divide both sides by 4.
4x/4 = 48/4
x = 12
Check answer.
12 + (3(12) + 15) = 63
12 + 36 + 15 = 63
63 = 63
Answer:
42
Step-by-step explanation:
Angle ABD = Angle CBD + Angle ABC
You know ABD is 70, CBD and ABC are in terms of x
70 = 5x + 13 + 3x + 33
70 - 13 - 33 = 8x
24 = 8x
3 = x
Replacing x in Angle ABC:
3 * 3 + 33 = 42