Answer:
the least integer for n is 2
Step-by-step explanation:
We are given;
f(x) = ln(1+x)
centered at x=0
Pn(0.2)
Error < 0.01
We will use the format;
[[Max(f^(n+1) (c))]/(n + 1)!] × 0.2^(n+1) < 0.01
So;
f(x) = ln(1+x)
First derivative: f'(x) = 1/(x + 1) < 0! = 1
2nd derivative: f"(x) = -1/(x + 1)² < 1! = 1
3rd derivative: f"'(x) = 2/(x + 1)³ < 2! = 2
4th derivative: f""(x) = -6/(x + 1)⁴ < 3! = 6
This follows that;
Max|f^(n+1) (c)| < n!
Thus, error is;
(n!/(n + 1)!) × 0.2^(n + 1) < 0.01
This gives;
(1/(n + 1)) × 0.2^(n + 1) < 0.01
Let's try n = 1
(1/(1 + 1)) × 0.2^(1 + 1) = 0.02
This is greater than 0.01 and so it will not work.
Let's try n = 2
(1/(2 + 1)) × 0.2^(2 + 1) = 0.00267
This is less than 0.01.
So,the least integer for n is 2
Answer:
B. 3 square feet
Step-by-step explanation:
The formula for surface area is:
2lw+2lh+2wh
Box F's surface area is just plugging in those variables
2(3)(3)+2(3)(3)+2(3)(3)=54
Box J's surface area is the same way
2(2)(4.5)+2(2)(3)+2(4.5)(3)=57
The difference is 57-54=3
The answer is B. 3 square ft
Answer:
$58.25
Step-by-step explanation:
142.20 - 24.50 = 117.50
117.50 / 2 = 58.25
The area of the circle is <span>112.98 m squared</span>
So here. I don't know how to explain so-
