Use the cosine ratio, as you have the adjacent and hypoteneuse.
So, set up cos50=2/x, but with the variable on the bottom,the cos50 and x switch places
x=2/cos50
x=3.11
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Answer: My bad if I butchered any answers. It was hard to read tbh
Step-by-step explanation:
D.) You can only factor out an x here. So you'd get: ![x(x^2-2x+4)](https://tex.z-dn.net/?f=x%28x%5E2-2x%2B4%29)
E.) You can factor out a 3x^2y to get: ![3x^2y(2-x)](https://tex.z-dn.net/?f=3x%5E2y%282-x%29)
F.) You can factor out a 3xy to get: ![3xy(y+3x-2)](https://tex.z-dn.net/?f=3xy%28y%2B3x-2%29)
G.) You can factor out a -4ab to get: ![-4ab(a-4b+2)](https://tex.z-dn.net/?f=-4ab%28a-4b%2B2%29)
Answer:
Step-by-step explanation:
cos a cos b+sin a sin b=cos (a-b)
cos 160 cos 10+sin 160 sin 10=cos (160-10)
=cos 150
=cos (180-30)
=-cos 30
=-√3/2
Answer:
x=-12 and -3
Step-by-step explanation:
The quadratic formula is
.
It is important because while some quadratics are factorable and can be solved not all are. The formula will solve all quadratic equations and can also give both real and imaginary solutions. We will substitute a=1, b=15 and c=36.
![x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}\\x=\frac{-15+/-\sqrt{(15)^2-4(1)(36)} }{2(1)}\\x=\frac{-15+/-\sqrt{225-144} }{2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%2B%2F-%5Csqrt%7Bb%5E2-4ac%7D%20%7D%7B2a%7D%5C%5Cx%3D%5Cfrac%7B-15%2B%2F-%5Csqrt%7B%2815%29%5E2-4%281%29%2836%29%7D%20%7D%7B2%281%29%7D%5C%5Cx%3D%5Cfrac%7B-15%2B%2F-%5Csqrt%7B225-144%7D%20%7D%7B2%7D)
We will now simplify and solve.
![x=\frac{-15+/-\sqrt{81}}{2}\\x=\frac{-15+/-9}{2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-15%2B%2F-%5Csqrt%7B81%7D%7D%7B2%7D%5C%5Cx%3D%5Cfrac%7B-15%2B%2F-9%7D%7B2%7D)
x=-12 and x=-3