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Ierofanga [76]
3 years ago
7

Please please factor fully.

Mathematics
2 answers:
kiruha [24]3 years ago
6 0

Answer:

d ) x( x^2 - 2x + 4 )

e ) 3x^2y( 2 - xy )

f ) 3xy( y + 3x - 2 )

g ) - 4ab( a - 4b + 2 )

Step-by-step explanation:

Let me just clarify whether these were the right expressions before considering the answer;

d ) x^3 - 2x^2 + 4x\\e ) 6x^2y - 3x^3y^2\\f ) 3xy^2 + 9x^2y - 6xy\\g ) - 4a^2 + 16ab^2 - 8ab

Now take a look at the explanation( s ) below;

x^3 - 2x^2 + 4x\\Common Term = x,\\\\Factored Expression = x \left(x^2-2x+4\right)

___________________________________

6x^2y - 3x^3y^2\\Common Term = 3x^2y,\\\\Factored Expression = 3x^2y\left(2-xy\right)

____________________________________

3xy^2 + 9x^2y - 6xy,\\Common Term = 3xy,\\\\Factored Expression = 3xy\left(y+3x-2\right)

____________________________________

- 4a^2b + 16ab^2 - 8ab,\\Common Term = - 4ab,\\\\Factored Expression = -4ab\left(a-4b+2\right)

<em>Hope that helps!</em>

Alekssandra [29.7K]3 years ago
4 0

Answer: My bad if I butchered any answers. It was hard to read tbh

Step-by-step explanation:

D.) You can only factor out an x here. So you'd get: x(x^2-2x+4)

E.) You can factor out a 3x^2y to get: 3x^2y(2-x)

F.) You can factor out a 3xy to get: 3xy(y+3x-2)

G.) You can factor out a -4ab to get: -4ab(a-4b+2)

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