The odds in favor of winning a prize in the contest of the juice company which gives prizes to anyone finding specially marked caps is 3.2.
<h3>What is odds against?</h3>
In probability, the term odds against is the ratio of probability of non occurring a favorable event to the probability of occurring a favorable event. It can be given as,
![\text{odd against}=\dfrac{P(\overline A)}{P(A)}](https://tex.z-dn.net/?f=%5Ctext%7Bodd%20against%7D%3D%5Cdfrac%7BP%28%5Coverline%20A%29%7D%7BP%28A%29%7D)
Here,
is the probability of not occurring a favorable event, and P(A) is the probability of occurring a favorable event.
A juice company gives the prizes to anyone finding specially marked caps on its juice bottles. The 4 bottles have winning cap in 20 bottles. Thus, the probability of winning is,
![P(A)=\dfrac{4}{20}\\P(A)=\dfrac{1}{5}](https://tex.z-dn.net/?f=P%28A%29%3D%5Cdfrac%7B4%7D%7B20%7D%5C%5CP%28A%29%3D%5Cdfrac%7B1%7D%7B5%7D)
The probability of not winning is,
![P(\overline A)=1-\dfrac{1}{5}\\P=\dfrac{4}{5}](https://tex.z-dn.net/?f=P%28%5Coverline%20A%29%3D1-%5Cdfrac%7B1%7D%7B5%7D%5C%5CP%3D%5Cdfrac%7B4%7D%7B5%7D)
Thus, the odd against the winning is,
![\text{odd against}=\dfrac{\dfrac{4}{5}}{\dfrac{1}{4}}\\\text{odd against}=\dfrac{16}{5}\\\text{odd against}=3.2](https://tex.z-dn.net/?f=%5Ctext%7Bodd%20against%7D%3D%5Cdfrac%7B%5Cdfrac%7B4%7D%7B5%7D%7D%7B%5Cdfrac%7B1%7D%7B4%7D%7D%5C%5C%5Ctext%7Bodd%20against%7D%3D%5Cdfrac%7B16%7D%7B5%7D%5C%5C%5Ctext%7Bodd%20against%7D%3D3.2)
Thus, the odds in favor of winning a prize in the contest of the juice company which gives prizes to anyone finding specially marked caps is 3.2.
Learn more about the odds against here;
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Answer: last option
Step-by-step explanation:
You know that the weight of his pumpkin 4.9 pounds and that, if he guesses its weight within 0.3 pounds, he will get the pumpkin for free.
Then, to find the minimum weight he can guess in order to get his pumpkin for free, it's necessary to write the expression:
![x-0.3=4.9](https://tex.z-dn.net/?f=x-0.3%3D4.9)
Rewriting it:
![x-4.9=0.3](https://tex.z-dn.net/?f=x-4.9%3D0.3)
To find the maximum weight he can guess in order to get his pumpkin for free, it's necessary to write the expression:
![x+0.3=4.9](https://tex.z-dn.net/?f=x%2B0.3%3D4.9)
Rewriting it:
![x-4.9=-0.3](https://tex.z-dn.net/?f=x-4.9%3D-0.3)
8 and 12 are separated by 1 line, and they have a difference of 4 units, so..
count every two lines and add 4 units
this means that the blue dot is 20
Step-by-step explanation:
The Taylor series expansion is:
Tₙ(x) = ∑ f⁽ⁿ⁾(a) (x − a)ⁿ / n!
f(x) = 1/x, a = 4, and n = 3.
First, find the derivatives.
f⁽⁰⁾(4) = 1/4
f⁽¹⁾(4) = -1/(4)² = -1/16
f⁽²⁾(4) = 2/(4)³ = 1/32
f⁽³⁾(4) = -6/(4)⁴ = -3/128
Therefore:
T₃(x) = 1/4 (x − 4)⁰ / 0! − 1/16 (x − 4)¹ / 1! + 1/32 (x − 4)² / 2! − 3/128 (x − 4)³ / 3!
T₃(x) = 1/4 − 1/16 (x − 4) + 1/64 (x − 4)² − 1/256 (x − 4)³
f(x) = 1/x has a vertical asymptote at x=0 and a horizontal asymptote at y=0. So we can eliminate the top left option. That leaves the other three options, where f(x) is the blue line.
Now we have to determine which green line is T₃(x). The simplest way is to notice that f(x) and T₃(x) intersect at x=4 (which makes sense, since T₃(x) is the Taylor series centered at x=4).
The bottom right graph is the only correct option.
Answer:
The principal amont was $35,000
Step-by-step explanation:
This is a simple interest problem.
The simple interest formula is given by:
![E = P*I*t](https://tex.z-dn.net/?f=E%20%3D%20P%2AI%2At)
In which E are the earnings, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time.
In this problem, we have that:
![E = 18375, t = 10, I = 0.0525](https://tex.z-dn.net/?f=E%20%3D%2018375%2C%20t%20%3D%2010%2C%20I%20%3D%200.0525)
We want to find P. So
![E = P*I*t](https://tex.z-dn.net/?f=E%20%3D%20P%2AI%2At)
![18375 = P*0.0525*10](https://tex.z-dn.net/?f=18375%20%3D%20P%2A0.0525%2A10)
![0.525P = 18375](https://tex.z-dn.net/?f=0.525P%20%3D%2018375)
![P = \frac{18375}{0.525}](https://tex.z-dn.net/?f=P%20%3D%20%5Cfrac%7B18375%7D%7B0.525%7D)
![P = 35000](https://tex.z-dn.net/?f=P%20%3D%2035000)
The principal amont was $35,000