Question

{3y-1}{2} =\frac{6y+3}{11}" alt="10-\frac{3y-1}{2} =\frac{6y+3}{11}" align="absmiddle" class="latex-formula">
y=
If you don't know don't answer. I will give you Brainliest if correct.

Answer 1

$10-\frac{3x-1}{2} =\frac{6x+3}{11}$

$10 = \frac{6x+3}{11} + \frac{3x-1}{2}$

$10 = (\frac{6x+3}{11} \times \frac{2}{2} ) + (\frac{3x-1}{2} \times \frac{11}{11} )$

$10 = ( \frac{2(6x + 3)}{22} ) + ( \frac{11(3x - 1)}{22} )$

$10 = \frac{12x + 6}{22} + \frac{33x - 11}{22}$

$10 = \frac{12x + 6 + 33x - 11}{22}$

$10 = \frac{(12 x + 33x) + (6 - 11)}{22}$

$10 = \frac{45x - 5}{22}$

$10 \times 22 = 45x - 5$

$220 = 45x - 5$

$220 + 5 = 45x$

$225 = 45x$

$\frac{225}{45} = x$

$\frac{45}{9} = x$

$5 = x$