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1 year ago

5

Aakesh has two bags of marbles. The first bag contains 6 red marbles, 5 blue

1 answer:

swat321 year ago

8 0

Answer:

A

Step-by-step explanation:

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Divisibility rules for 2, 5, and 10

Simora [160]

Answer:

none of these

Step-by-step explanation:

A number is divisible by 10 if the last digit of the number is 0. The numbers 20, 40, 50, 170, and 990 are all divisible by 10 because their last digit is zero, 0.

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3 years ago

Pls help me calculate the total area of compound shapes?!?!?

alexandr1967 [171]

Answer:

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2 years ago

Given the function f(x) = -5|x + 1| + 3, for what values of x is f(x) = -12? O X= -2. x = 1 O x= -2 x = 4 O x = 2. x = 4 O x = 2

puteri [66]

The values are x= -2 and x =4 of the given function f (x) =-5|x+1| +3

<h3>What is function?</h3>

Function is an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable).

According to the question,

The given function is

$f(x) = -5|x + 1| + 3$

Here f(x) = -12

Substitute f(x) and solve for x

$- 12 = -5|x + 1| + 3$

By subtracting 3 on both sides

$- 12 - 3 = -5|x + 1| + 3 - 3$

$- 15 = -5|x + 1|$

By dividing -5 on both sides

$3 = |x + 1|$

We get absolute values for the function.

$x + 1 = 3 , x + 1 = -3$

By subtracting 1 on both sides

$x + 1 - 1 = 3 - 1 = 2\\\\x + 1 - 1 = - 3 - 1 = -4\\\\x = 2 , x = - 4$

Therefore, the values of x are 2 and - 4 of the given function f (x) =-5|x+1| +3

Learn more about function here: brainly.com/question/12431044

#SPJ1

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1 year ago

Helpppppppppppppppppppp

Sloan [31]

Answer:

Sum of $\frac{7x}{x^2-4}$ and $\frac{2}{x+2}$ is $\mathbf{\frac{9x-4}{x^2-4}}$

Option B is correct answer.

Step-by-step explanation:

We need to find sum of $\frac{7x}{x^2-4}$ and $\frac{2}{x+2}$

Finding sum of $\frac{7}{x^2-4}$ and $\frac{2}{x+2}$ :

$\frac{7x}{x^2-4}+\frac{2}{x+2}$

We know that $x^2-4 =(x+2)(x-2)$

Replacing x^2-4

$\frac{7x}{(x+2)(x-2)}+\frac{2}{x+2}$

Now, taking LCM of (x+2)(x-2) and (x+2) we get (x+2)(x-2)

$=\frac{7x+2(x-2)}{(x+2)(x-2)}\\=\frac{7x+2x-4}{(x+2)(x-2)}\\=\frac{9x-4}{(x+2)(x-2)}\\=\frac{9x-4}{x^2-4}$

So, Sum of $\frac{7x}{x^2-4}$ and $\frac{2}{x+2}$ is $\mathbf{\frac{9x-4}{x^2-4}}$

Option B is correct answer.

6 0

2 years ago

What is 3.06 rounded each number to the nearest tenths?

g100num [7]

3.1
......................

6 0

3 years ago