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cupoosta [38]
3 years ago
8

How do i solve this question 58−(14)2

Mathematics
2 answers:
lyudmila [28]3 years ago
6 0

Answer:

Step-by-step explanation:

58-(14)2

58-28

=30

Naily [24]3 years ago
3 0

Answer:

PEMDAS RULE

Step-by-step explanation:

STEP one is multiplication 58-14x2=58-28

STEP two is subtraction 58-28=30

Parenthesis

Exponent

Multiplication

Division

Addition

Subtract

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Three single-digit numbers multiply to make 504 Write the missing numbers
boyakko [2]
We will guess and check to solve this problem

504/9= 56
504/8= 63
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we can continue the pattern. However, we know that 50 is the product of 8 and 7, so we can use that number

9*8*7=504
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Ursula tosses two six-sided number cubes and MULTIPLIES the numbers rolled. Which of these is a list of the outcomes of the two
Black_prince [1.1K]

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3,4,5,6,7,8

Step-by-step explanation:

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3 years ago
What does 3,146 round to nearest thousand
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4 0
3 years ago
(Anderson, 1.14) Assume that P(A) = 0.4 and P(B) = 0.7. Making no further assumptions on A and B, show that P(A ∩ B) satisfies 0
Goshia [24]

Answer with Step-by-step explanation:

We are given that

P(A)=0.4 and P(B)=0.7

We know that

P(A)+P(B)+P(A\cap B)=P(A\cup B)

We know that

Maximum value of P(A\cup B)=1 and minimum value of P(A\cup B)=0

0\leq P(A\cup B )\leq 1

0\leq P(A)+P(B)-P(A\cap B)\leq 1

0\leq 0.4+0.7-P(A\cap B)\leq 1

0\leq 1.1-P(A\cap B)\leq 1

0\leq 1.1-P(A\cap B)

P(A\cap B)\leq 1.1

It is not possible that P(A\cap B) is equal to 1.1

1.1-P(A\cap B)\leq 1

-P(A\cap B)\leq 1-1.1=-0.1

Multiply by (-1) on both sides

P(A\cap B)\geq 0.1

Again, P(A\cup B)\geq P(B)

0.4+0.7-P(A\cap B)\geq 0.7

1.1-P(A\cap B)\geq 0.7

-P(A\cap B)\geq -1.1+0.7=-0.4

Multiply by (-1) on both sides

P(A\cap B)\leq 0.4

Hence, 0.1\leq P(A\cap B)\leq 0.4

3 0
3 years ago
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