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2 years ago

12(x - 3) + 18 = 4(3x - 3)

Mathematics

1 answer:

k0ka [10]2 years ago

4 0

Answer:

No Solution

x = 1/2

x = -5

x = 1

No Solution

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Find the 84th percentile

morpeh [17]

Answer:

Roughly speaking, in a normal distribution, a score that is 1 s.d. above the mean is equivalent to the 84th percentile. ... In other words, roughly 95 percent of students are within two standard deviations – positive or negative – of the average

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2 years ago

Leo's age is three times Stan’s age. In five years, Leo will be twice as old as Stan. How old is each now?

aleksandr82 [10.1K]

Answer:

Step-by-step explanation:

L=3S

In 5 years,

L+5=2(S+5)

L+5=2S+10

L=2S+5

Substituting from above,

3S=2S+5

S=5

So then,

L=3(5)

L=15

6 0

3 years ago

If a fashion store receives $42.56 in commission from the sales she made on Friday and her commission rate was 8%, what was the

solniwko [45]

She made 3.41 in commission.

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3 years ago

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I need help ok help meeee

uysha [10]

It’s a bit blurry retake the picture

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3 years ago

Walk fifty meters at 30o north or east from the old oak tree. (2) Turn 45o to your left (you should now be facing 75o north of e

saw5 [17]

Answer:

A straight line of approximately 75 meters, 1.4º north

Step-by-step explanation:

Hi, let's make it step by step to make it clearer

1) If we walk 50 meters in 30º angle Northeast, assuming the Old Oak tree is the point 0,0 and we're dealing with vectors in $R^{2}$ . To say 30º Northeast is 30º clockwise (or 60º counter clockwise).

2) Then there was a the turning point to the left. If I turn to the left, on my compass 45º , I'll face 75º northeast.

3) Finally, the last vector leads to the treasure from the Old Oak Tree, i.e. the resultant.

So, let's calculate the norm which is the length of the each vector.

1) Graphing them we can find the points, then the components and then calculate the norm, the length of each vector.

Since the Oak Tree is on (0,0). The turning point (50,86.61) and the Rock (R=(1.4,74,85) we can write the following vectors:

$\vec{u}=\left \langle 50,86.61 \right \rangle\\\vec{v}=\left \langle -48.6,-11.76\right \rangle\\\vec{w}=\left \langle 1.4,74.85 \right \rangle$

Now, let's calculate each vector length by calculating the norm.

$\left \| \vec{u} \right \|=\sqrt{50^{2}+86.6^2}=100\\\left \| \vec{v} \right \|=\sqrt{(-48.6)^2+(-11.76)^2}=50\\\left \| \vec{u} \right \|=\sqrt{(1.4)^2+(74.85)^2}=74.86$

The path is almost 75 meters. And since it is less than 15º degrees to the left of the North (or to the right) its direction is still north of the Old Oak Tree.

8 0

3 years ago