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Andrej [43]
2 years ago
6

Which is government departments fund the Global Positioning System

Computers and Technology
1 answer:
ArbitrLikvidat [17]2 years ago
6 0

Answer:

The department of defense

Explanation:

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Write a program that lets the user enter the total rainfall for each of 12 months (starting with January) into an array of doubl
lianna [129]

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The C++ code is given below with appropriate comments

Explanation:

#include "stdafx.h"

//Header file section

#include <iostream>

#include <iomanip>

#include <string>

using namespace std;

//Function prototypes

double rainfallTotal(double[], int);

double averageMonthlyRainfall(double[], int);

double highestAmountRainfall(double[], int, int &);

double lowestAmountRainfall(double[], int, int &);

int main()

{

//Initialize variables

const int ALL_MONTHS = 12;

int highIndex = 0;

int lowIndex = 0;

//Declare variables

double totalRf;

double averageRf;

double mostRf;

double leastRf;

double monthlyRf[ALL_MONTHS];

string monthName[ALL_MONTHS] = { "January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December" };

for (int i = 0; i < ALL_MONTHS; i++)

{

 cout << "Enter rainfall for " << monthName[i] << ": ";

 cin >> monthlyRf[i];

 // Check the input as negative numbers

 //for monthly rainfall

 while (monthlyRf[i] < 0)

 {

  cout << "Invalid data (negative rainfall) " << endl;

  cout << "Retry the rainfall in " << monthName[i] << ": ";

  cin >> monthlyRf[i];

 }

}

//Call the methods

totalRf = rainfallTotal(monthlyRf, ALL_MONTHS);

averageRf = averageMonthlyRainfall(monthlyRf, ALL_MONTHS);

mostRf = highestAmountRainfall(monthlyRf, ALL_MONTHS, highIndex);

leastRf = lowestAmountRainfall(monthlyRf, ALL_MONTHS, lowIndex);

//Display output

cout << fixed << showpoint << setprecision(2) << endl;

cout << "Total rainfall: " << totalRf << endl;

cout << "Average rainfall: " << averageRf << endl;

cout << "Least rainfall in " << monthName[lowIndex] <<endl;

cout << "Most rainfall in " << monthName[highIndex] <<endl;

system("pause");

return 0;

}

//Method definition of rainfallTotal

double rainfallTotal(double totalRainfall[], int n)

{

double total = 0;

for (int i = 0; i < n; i++)

 total += totalRainfall[i];

return total;

}

//Method definition of averageMonthlyRainfall

double averageMonthlyRainfall(double totalRainfall[], int n)

{

double average = 0.0;

double total = 0;

for (int i = 0; i < n; i++)

 total += totalRainfall[i];

average = total / n;

return average;

}

//Method definition of lowestAmountRainfall

double lowestAmountRainfall(double totalRainfall[], int n, int &monthIndex)

{

double least;

int i = 0;

least = totalRainfall[i];

while (i < n)

{

 if (totalRainfall[i] < least)

 {

  least = totalRainfall[i];

  monthIndex = i;

 }

 i++;

}

return least;

}

//Method definition of highestAmountRainfall

double highestAmountRainfall(double totalRainfall[], int n, int &monthIndex)

{

double high;

int i = 0;

high = totalRainfall[i];

while (i < n)

{

 if (totalRainfall[i] > high)

 {

  high = totalRainfall[i];

  monthIndex = i;

 }

 i++;

}

return high;

}

3 0
3 years ago
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