Answer:
public static void removeInRange(List<Integer> list, int value, int start, int end) {
for (int i = end - 1; i >= start; i--) {
if (list.get(i) == value) {
list.remove(i);
}
}
System.out.println(list);
}
Explanation:
- Create a method named <em>removeInRange</em> that takes four parameters, a list, an integer number, a starting index and an ending index
- Inside the method, initialize a <u>for loop</u> that iterates between starting index and ending index
- If any number between these ranges is equal to the given <em>value</em>, then remove that value from the list, using <u>remove</u> method
- When the loop is done, print the new list
Assembly language, a.k.a. machine language.
Answer:
You must add atmospheric pressure
Explanation:
The unit for gauge pressure is PSIA. You convert between them by adding or subtracting atmospheric pressure. 1 PSIG = 1 PSIA - atm and conversely: 1 PSIA = 1 PSIG + atm.
Answer:
Option B.
Explanation:
The delete key is used to delete the symbol after the insertion point.
Here, Michal is typed as Michael.
So, to delete the letter e from Michael, put the insertion point before e.
If you put insertion point after the letter e or before the letter l, l gets deleted.
In no case, you can put the insertion point after the letter l.
So, option B is correct.