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yawa3891 [41]
3 years ago
5

12a - 7 + 4a + 8 What is the answer

Mathematics
2 answers:
OverLord2011 [107]3 years ago
7 0
<span>12a - 7 + 4a + 8
Add 4a to 12a while adding 8 to -7
Final Answer: 16a + 1</span>
weeeeeb [17]3 years ago
6 0
16a+1 is the answer to your question
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A sequence is defined by the following:
katrin2010 [14]

Answer:

Step-by-step explanation:

a1 = 6

a2 = -1.2*a_(n-1)

a2 = -1.2*a_1

a2 = -1.2 * 6

a2 = -7.2

a3 = -1.2*a_(n-1)

a3 = -1.2*a_2

a3 = -1.2 * - 7.2

a3 = 8.64

a4 = -1.2 * a_3

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6 0
4 years ago
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Find the mean, median, mode, and range of the data 10, 13, 7, 6, 9, 4, 6, 3, 5​
elena-s [515]
Median is 6 range is 9 mode is 6 and mean is 7
7 0
3 years ago
A rancher plans to make 4 identical and adjacent rectangular pens against a barn (see figure below), each with an area of 100 m^
Tasya [4]

Answer:

10 by 10 meters

Step-by-step explanation:

In calculus terms, you can use the formula for the perimeter which is 2l + 2w, and the area l × w.

Then since the area is 100

l × w = 100. So w = 100/l

Then substitute this into the perimeter formula.

w = 100/l → 2l + 2(w) = 2l + 2(100/l) = 2l + 200/l.

Then take the derivative d/dx [take the derivative of a quantity with respect to x], by using a simpler method known as the power rule:

d/dx[x^n] = nx^n-1

so p = 2l + 200/l becomes p' = 2 - 200/l^2

Since the derivative of a constant is 0, to solve for l, set p' to 0

0 = 2 - 200/l^2 → -200/l^2 = -2 → 200/l^2 = 2 → 2l^2 = 200 → l^2 = 100 → l = √100, l = 10.

Now that we know the length is 10, We can substitute the length in the original equation to find the width.

l = 10 → w = 100/l → w = 100/10, w = 10.

Therefore the perimeter of each rectangular pen is 40, with a length of 10 and width of 10.

If you want to do this algebraicly, there are more steps involved

7 0
3 years ago
Rewrite in simplest terms: 3(q-2r)+6r-8(-6r-2q)3(q−2r)+6r−8(−6r−2q)
Airida [17]

Mom and dad go down

The drain

4 0
3 years ago
Two cables support a 800​-lb ​weight, as shown. Find the tension in each cable.
jeka94

Answer:

  • 892 lb (right)
  • 653 lb (left)

Step-by-step explanation:

The weight is in equilibrium, so the net force on it is zero. If R and L represent the tensions in the Right and Left cables, respectively ...

  Rcos(45°) +Lcos(75°) = 800

  Rsin(45°) -Lsin(75°) = 0

Solving these equations by Cramer's Rule, we get ...

  R = 800sin(75°)/(cos(75°)sin(45°) +cos(45°)sin(75°))

     = 800sin(75°)/sin(120°) ≈ 892 . . . pounds

  L = 800sin(45°)/sin(120°) ≈ 653 . . . pounds

The tension in the right cable is about 892 pounds; about 653 pounds in the left cable.

_____

This suggests a really simple generic solution. For angle α on the right and β on the left and weight w, the tensions (right, left) are ...

  (right, left) = w/sin(α+β)×(sin(β), sin(α))

5 0
3 years ago
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