Ask question

Ask question

All categories

-Dominant- [34]

2 years ago

9

Describe the reflection of the figure. A) reflection over the x-axis B) reflection over the y-axis C) reflection over the line y

= 4 D) reflection over the line y = −4

1 answer:

Gre4nikov [31]2 years ago

7 0

Answer:

A) reflection over the x-axis

Step-by-step explanation:

You might be interested in

Evaluate the following expressions:<br> 1. 5(a+2b)-3b

Alika [10]

Answer:

=5a+7b

Step-by-step explanation:

Expand: 5(a + 2b): 5a + 10b
=5a+10b-3b
<em>Add similar elements: 10b-3b=7b
</em>=5a +7b

4 0

2 years ago

Read 2 more answers

How are the real solutions of a quadratic equation related to the graph of the quadratic function?

Anika [276]

The solutions you get when you solve the formula are the corresponding y coordinates to your x value. So say a point on your graph is (2,3). The first number is x and the second is y. (x,y). The number you plug into your function is x,or in this case: 2. The solution to the equation when the x value is plugged in is y, or 3. Therefore, giving you a point on your graph.

7 0

3 years ago

SERIOUSLY HELPPPPPPPP

AlekseyPX

9514 1404 393

Answer:

B.

as x increases, f(x) decreases;
as x decreases,f(x) decreases

Step-by-step explanation:

The function is of even degree with a negative leading coefficient. f(x) will tend toward negative infinity as x gets larger or smaller. That is ...

as x increases, f(x) decreases;
as x decreases,f(x) decreases

_____

<em>Even degree</em> means the end behaviors are the same for both large and small x. <em>Negative leading coefficient</em> means the function value decreases for larger x.

8 0

3 years ago

Help pls 20 points due today

Alona [7]

Answer: A

Step-by-step explanation:

3 0

3 years ago

How do I solve: 2 sin (2x) - 2 sin x + 2√3 cos x - √3 = 0

ziro4ka [17]

Answer:

$\displaystyle x = \frac{\pi}{3} +k\, \pi$ or $\displaystyle x =- \frac{\pi}{3} +2\,k\, \pi$ , where $k$ is an integer.

There are three such angles between $0$ and $2\pi$ : $\displaystyle \frac{\pi}{3}$ , $\displaystyle \frac{2\, \pi}{3}$ , and $\displaystyle \frac{4\,\pi}{3}$ .

Step-by-step explanation:

By the double angle identity of sines:

$\sin(2\, x) = 2\, \sin x \cdot \cos x$ .

Rewrite the original equation with this identity:

$2\, (2\, \sin x \cdot \cos x) - 2\, \sin x + 2\sqrt{3}\, \cos x - \sqrt{3} = 0$ .

Note, that $2\, (2\, \sin x \cdot \cos x)$ and $(-2\, \sin x)$ share the common factor $(2\, \sin x)$ . On the other hand, $2\sqrt{3}\, \cos x$ and $(-\sqrt{3})$ share the common factor $\sqrt[3}$ . Combine these terms pairwise using the two common factors:

$(2\, \sin x) \cdot (2\, \cos x - 1) + \left(\sqrt{3}\right)\, (2\, \cos x - 1) = 0$ .

Note the new common factor $(2\, \cos x - 1)$ . Therefore:

$\left(2\, \sin x + \sqrt{3}\right) \cdot (2\, \cos x - 1) = 0$ .

This equation holds as long as either $\left(2\, \sin x + \sqrt{3}\right)$ or $(2\, \cos x - 1)$ is zero. Let $k$ be an integer. Accordingly:

$\displaystyle \sin x = -\frac{\sqrt{3}}{2}$ , which corresponds to $\displaystyle x = -\frac{\pi}{3} + 2\, k\, \pi$ and $\displaystyle x = -\frac{2\, \pi}{3} + 2\, k\, \pi$ .
$\displaystyle \cos x = \frac{1}{2}$ , which corresponds to $\displaystyle x = \frac{\pi}{3} + 2\, k \, \pi$ and $\displaystyle x = -\frac{\pi}{3} + 2\, k \, \pi$ .

Any $x$ that fits into at least one of these patterns will satisfy the equation. These pattern can be further combined:

$\displaystyle x = \frac{\pi}{3} + k \, \pi$ (from $\displaystyle x = -\frac{2\,\pi}{3} + 2\, k\, \pi$ and $\displaystyle x = \frac{\pi}{3} + 2\, k \, \pi$ , combined,) as well as
$\displaystyle x =- \frac{\pi}{3} +2\,k\, \pi$ .

7 0

3 years ago