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2 years ago

9. Identify the correct property being shown.

Mathematics

2 answers:

BaLLatris [955]2 years ago

4 0

Answer:

-16.4, (commutative property)

Step-by-step explanation:

(add, because they are both negatives) -5.2+(-8.4)= -13.6

Then add the (-2.8): -13.6 + (-2.8) = -16.4

Thats your first equation!!!

do the same thing for the other one, and by the way it the same answer.

Its commutative prop because its just switching positions and its adding negatives.

mixer [17]2 years ago

4 0

The answer above me :))

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Quadrilateral DEFG has at least one pair of opposite sides congruent. What types of quadrilaterals meet this condition?

zhuklara [117]

Answer:

Parallelogram, Rectangle, Square, Rhombus, Trapezoid. ... ANSWER Trapezoid: there is one pair of parallel sides

Step-by-step explanation:

there is one pair of parallel sides

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2 years ago

How do i simplify this expression? 3(a-7)=?

kolbaska11 [484]

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Step-by-step explanation:

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3 years ago

Two equivalent ratios for 14/8

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14 to 8
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3 years ago

Last month your profit as a percentage of revenue was 10% and you made a profit of 23,224 what’s your total revenue

Svetlanka [38]

Answer:

232,240

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3 years ago

Please help me with circle questions below

IRINA_888 [86]

For first question, What is approximate value of "......" this part is missing so please write whose approximate value question is asking to find

For second question we have to find $tan\Theta$

In right triangle ABC as show in attachment,

$tan\Theta = \frac{opposite side}{adjacent side} = \frac{AB}{BC}$ ----(1)

Now AB is given by distance of point A from x axis which will be given by its y - coordinate. So $AB = \frac{1}{2}$

Similarly BC is the distance of point A from y axis (horizontal distance ) and that will be given by x coordinate of A. So $BC = \frac{\sqrt{3}}{2}$

Plug these values in equation (1)

$tan\Theta = \frac{AB}{BC} = \frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}}$

To divide fractions we flip (reciprocal ) bottom fraction and multiply it to top fraction as shown

$tan\Theta = \frac{1}{2} \times \frac{2}{\sqrt{3}}$

Now 2 in top and bottom cancels out so we are left with

$tan\Theta = \frac{1}{\sqrt{3}}$

so thats the final answer for $tan\Theta$

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3 years ago