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3 years ago

Wright the expression 6a - 2 (a-1) in simplest form

Mathematics

1 answer:

vovikov84 [41]3 years ago

6 0

6a-2(a-1)
6a-2a-2
4a-2
I think it is 4a-2

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Help what is greater?45.10 or 45.01???

Anika [276]

45.10 is greater than 45.01

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3 years ago

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If X is a normally distributed random variable with mean .30 and standard deviation .06 : (draw appropriate diagrams) a) Find P(

Ierofanga [76]

Answer:

0.34 x 0.38

=0.1292

Step-by-step explanation:

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2 years ago

If all of the diagonals are drawn from a vertex of a quadrilateral, how many triangles are formed?

sergij07 [2.7K]

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2 years ago

The Panthers scored 13 more points than the Giants. The total of their scores was 47. How many points did each team score?

Licemer1 [7]

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2 years ago

A simple random sample of size n equals 200 individuals who are currently employed is asked if they work at home at least once p

____ [38]

Answer: 99% of confidence interval for the population proportion of employed individuals who work at home at-least once per week

//0.20113,0.20887[/tex]

Step-by-step explanation:

step 1:-

Given sample size n=200

of the 200 employed individuals surveyed 41 responded that they did work at home at least once per week

Population proportion of employed individuals who work at home at least once per week P = $\frac{x}{n} =\frac{41}{200} =0.205$

Q=1-P= 1-0.205 = 0.705

step 2:-

Now $\sqrt{\frac{P Q}{n} } =\sqrt{\frac{(0.205)(0.705)}{200} }$

=0.0015

step 3:-

Confidence intervals

using formula

$(P - Z_∝} \sqrt{\frac{P Q}{n},} (P + Z_∝} \sqrt{\frac{P Q}{n},$

$(0.205-2.58(0.0015),0.205+2.58(0.0015)\\0.20113,0.20887$

=0.20113,0.20887[/tex]

conclusion:-

99% of confidence interval for the population proportion of employed individuals who work at home at-least once per week

//0.20113,0.20887[/tex]

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3 years ago