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3 years ago

13

Bobs mom asked how he Had done on his math test . Bob said if you mupily my score by 3 then subtract 40 from they answer , then

divide by 2 you would get exactly 100 what was bob's score?

2 answers:

amid [387]3 years ago

8 0

Let bob score =x

according to given condition

(3x-40)/2=100

3x-40=200
3x=240
x=80
so bob score =80

siniylev [52]3 years ago

3 0

100*2 = 200
200+40=240
240/30= 80
Bob got an 80% on his test.

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Find the midpoint of the line segment with the endpoints A and B.

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Answer:

<h2>( 6 , 7 )</h2>

Step-by-step explanation:

The midpoint M of two endpoints of a line segment can be found by using the formula

$M = ( \frac{x1 + x2}{2} , \: \frac{y1 + y2}{2} )\\$

From the question we have

$m = ( \frac{2 + 10}{2} \: , \: \frac{6 + 8}{2} ) \\ = (\frac{12}{2} \: , \: \frac{14}{2} ) \: \: \: \: \: \: \:$

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<h3>( 6 , 7 )</h3>

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2 years ago

A contractor combined x tons of a gravel mixture that contained 10 percent gravel G, by weight, with y tons of a mixture that co

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Answer:

The value of x would be $\frac{3}{5}y$ or $\frac{3}{8}z$

Step-by-step explanation:

Given,

x tons of 10% gravel G mixture is mixed with y ton of 2% gravel G to obtain 5% gravel mixture,

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3 years ago

Write an equation of the circle that has a diameter with endpoints (12, 3) and<br> (-18,3).

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The equation of the circle that has a diameter with endpoints (12, 3) and(-18,3) is x² + y² + 6x - 6y - 207 = 0

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Since the endpoints of the diameter are (x₁, y₁) = (12,3) and (x₂, y₂) = (-18,3), the coordinates of the center of the circle are the midpoints of the diameter. So, the midpoints are

x = (x₁ + x₂)/2 = (12 + (-18))/2 = (12 - 18)/2 = -6/2 = -3 and
y = (y₁ + y₂)/2 = (3 + 3)/2 = 6/2 = 3.

So, the coordinates of the center of the circle are (-3, 3)

<h3>The radius of the circle</h3>

The radius of the circle r = √[(x₁ - h)² + (y₁ - k)²] where

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So, substituting the values of the variables into r, we have

r = √[(x₁ - h)² + (y₁ - k)²]

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The equation of a circle with center (h,k) is given by

(x - h)² + (y - k)² = r² where r = radius of circle.

Substituting the values of the variables into the equation, we have

(x - h)² + (y - k)² = r²

(x - (-3))² + (y - 3)² = 15²

(x + 3)² + (y - 3)² = 15²

x² + 6x + 9 + y² - 6y + 9 = 225

x² + 6x + y² - 6y + 9 + 9 - 225 = 0

x² + y² + 6x - 6y - 207 = 0

The equation of the circle that has a diameter with endpoints (12, 3) and(-18,3) is x² + y² + 6x - 6y - 207 = 0

Learn more about equation of a circle here:

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Answer:

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3 years ago

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