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Nata [24]
3 years ago
13

Helpppp pleaseeeee please

Mathematics
1 answer:
Korolek [52]3 years ago
8 0
\bold{ANSWER:}
28

\bold{SOLUTION:}

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A politician's support grew from 42% by 3 percentage points to 45%. What percent (relative) change is this? Round your answer to
gregori [183]

Answer:

7.1%

Step-by-step explanation:

The formula for percentage relative change =

[Final value - Initial value/Initial value] × 100

From the above question

Initial value = 42 %

Final value = 45%

= 45 - 42/ 42 × 100

= 3/42 × 100

= 7.1428571429 %

Therefore, approximately to the nearest tenth, the percentage relative change = 7.1%

7 0
4 years ago
Jordan is, ordering a taxi from an online taxi service. The taxi charges $4 just for the
adell [148]

Answer: $8

Step-by-step explanation: The equation would be - 4+2m

7 0
3 years ago
Help me answer this question!<br>149/95 × 100 = ??? ​
n200080 [17]

Answer:

<em>1</em><em>5</em><em>7</em><em> </em>

Step-by-step explanation:

<em>1</em><em>4</em><em>9</em><em>/</em><em>9</em><em>5</em><em>*</em><em>100=</em><em>1</em><em>5</em><em>7</em><em> </em>

<em>I </em><em>hope</em><em> </em><em>it</em><em> </em><em>will </em><em>be</em><em> </em><em>helpful</em>

7 0
3 years ago
Read 2 more answers
Last week’s and this week’s low temperatures are shown in the table below. Low Temperatures for 5 Days This Week and Last Week L
STatiana [176]

Question:

Temperatures for 5 Days This Week and Last Week

Low Temperatures This Week (Degrees Fahrenheit) 4 10 6 9 6 Low Temperatures Last Week (Degrees Fahrenheit) 13 9 5 8 5 Which measures of center or variability are greater than 5 degrees? Select three choices.

a) the mean of this week’s temperatures

b) the mean of last week’s temperatures

c) the range of this week’s temperatures

d)the mean absolute deviation of this week’s temperatures

e) the mean absolute deviation of last week’s temperatures

Answer:

a) the mean of this week’s temperatures

b) the mean of last week’s temperatures

c) the range of this week’s temperatures

Step-by-step explanation:

I would be verifying the options a, b, and c in my answer above through calculations which are shown below.

We were given the following data:

Low Temperatures This Week (Degrees Fahrenheit)

4, 10, 6, 9, 6

Low Temperatures Last Week (Degrees Fahrenheit)

13, 9, 5, 8, 5

We are to find which measures of center or variability are greater than 5 degrees.

Option a

The mean of this week’s temperatures

(4+ 10+ 6+9+ 6) °F ÷ 5 = 35 °F ÷5 = 7°F

Option a is correct because it measures of center or variability which is 7 °F is higher than 5°F

Option b

The mean of last week’s temperatures

(13+ 9 + 5 + 8 + 5) °F = 40°F ÷ 5 = 8°F

Option b is correct , because its measure of variability which is 8°F is greater than 5°F.

Option c

the range of this week’s temperatures

This week's temperature is given as

(4, 10, 6, 9, 6) °F

Range is defined as the difference between the highest number and the lowest number

Range of this week's temperature = (10 - 4) °F = 6°F

Hence Option c is correct because it measures of center or variability which is 6°F is greater than 5°F

From the above calculations we can accurately confirm that options a, b, and c are correct because the measures of their center or variability is greater than 5°F

3 0
3 years ago
Read 2 more answers
Please help i need this done asap
ki77a [65]

Answer:

A

Step-by-step explanation:

Using the rules of exponents

a^{m} × a^{n} = a^{(m+n)}  , a^{-m} = \frac{1}{a^{m} }  , a^{0} = 1

(14x³y^{-4} )(4x^{-5}y^{4} )

= 14 × 4 × x³ × x^{-5} × y^{-4} × y^{4}

= 56 × x^{(3-5)} × y^{(-4+4)}

= 56 × x^{-2} × y^{0}

= 56 × \frac{1}{x^2} × 1

= \frac{56}{x^2} → A

8 0
3 years ago
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