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The data set below represents the ages of 11 kids in an after-school program. 10, 11, 8, 7, 6, 10, 7, 10, 9, 9, 12 Which box plo
Andreas93 [3]
Answer:
This is the answer because you need to find mean median mode range, first quertile, third quartile
Whisker plot below
Step-by-step explanation:
Mean (Average) 9
Median 9
Range 6
Mode 10, appeared 3 times
Geometric Mean 8.8206311297046
Largest 12
Smallest 6
Sum 99
Count 11
■ 1st quartile (lower quartile) = 7.5
■ 2st quartile (median) = 9
■ 3st quartile (upper quartile) = 10
Answer:
<em>C. 6 ⋅ 9 + 1 </em>
Step-by-step explanation:
Start with the multiplication:
"one more than the product of six and nine"
6 ⋅ 9
Now take care of the addition by adding 1 to the product.
"one more than the product of six and nine"
6 ⋅ 9 + 1
Answer: C. 6 ⋅ 9 + 1
Answer:
3135
Step-by-step explanation:
Givens
a1 = 6
Use t4 - t3 to get d
t4 = 27
t3 = 20
Step One
Find a1 and d
a1 = 6
d = t4 - t3
d = 27 - 20
d = 7
Step Two
Find the 30th Term
tn= a1 + (n -1 )*d
t30 = 6 + (30 - 1) * 7
t30 = 6 + 29*7
t30 = 6 + 203
t30 = 209
Step Three
Find the sum using Sum = (a + t30)*n/2
n = 30 given
a1 = 6 given
t30 = 209 calculated from step 2
Sum = (a1 + t30)*n/2 Substitute
Sum = (6+ 209)*30/2 Combine like terms and divide by 2
sum = 215 * 15 Multiply
Sum = 3135 Answer
The correct answer is C. The form for shifts is (x-h)^2 +k where h=the x variable ( horizontal shift left or right) and k = the y variable (vertical shift up or down) The confusing part for many students is remember that if you are moving left it's subtraction So in the form x-h it is actually x - (-h) so it gets turned into a positive/ addition sign.