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1 year ago

15

"Draw a line representing the "rise" and a line representing the "run" of the line. State the slope of the line in simplest form

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1 answer:

liberstina [14]1 year ago

8 0

The slope of the line = rise of the line / run of the line = 2/2 = 1.

<h3>How to Find the Slope of a Line?</h3>

The slope (m) of a line can be determined by finding the ratio of the rise of the line to the run of the line, which is, the change in y over the change in x.

Referring to the image attached below, the blue line in the given graph shows the rise of the line while the red line shows the run of the line.

Therefore:

Rise of the line = 2 units

Run of the line = 2 units

Slope of the line (m) = rise/run = 2 units/2 units

Slope of the line (m) = 1

Learn more about slope on:

brainly.com/question/13861479

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What is the area of the triangle that is 30 m base in the height of 12 m in a straight line of 13

Reika [66]

Answer:

60

Step-by-step explanation:

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3 years ago

Five packets of almonds cost 2m dollars. Mandy buys 3 packets of almonds. How much change does she receive if she paid with a $1

Vitek1552 [10]

Answer:

$4

Step-by-step explanation:

if its $2 per packet and he is buying 3 do 2x3 which is 6 then 10-6 which is $4

3 0

3 years ago

You purchase a car worth $25077 and make a down payment of $3560. You intend to repay the balance of the car with month end car

zubka84 [21]

Answer:

value of buyout is $4185.74

Step-by-step explanation:

given data

car worth = $25077

down payment = $3560

monthly payment = $336 = 336 × 6 = $2016 per semi annually

time = 5 year = 10 half yearly

rate = 4.04 %

to find out

value of final buyout

solution

we know here loan amount will be 25077 - 3560 = $21517

and we find present value first by formula that is

present value = $\frac{amount(1+r)^t - 1}{r (1+r)^t}$

put here t = 10 and r = $\frac{4.04}{200}$

so

present value = $\frac{2016(1+\frac{4.04}{200})^10 - 1}{r (1+\frac{4.04}{200})^10}$

present value = 18089.96

so

loan unpaid amount is here

loan unpaid amount = 21517 - 18089.96

loan unpaid amount = $3427.04

so

now we calculate value of buyout

that is express as

amount = principal × $(1+r)^{t}$

amount = 3427.04 × $(1+\frac{4.04}{200})^{10}$

amount = 4185.74

so value of buyout is $4185.74

7 0

4 years ago

A number is written with 10 zeros, 10 ones and 10 twos. Is it possible for it to be a perfect square ? Please help. I don’t unde

lora16 [44]

Answer:

i am going to help you to understand this problem. if it is written with 10 0s it will be the billion place. because of the ten ones it will be 0,000,010, and because of the ten two's, which is 20, it will be 0,000,030. and when i searched up on google, and watched an episode of number blocks, no, 30 is not a square number OR a cube number.

Step-by-step explanation:

8 0

3 years ago

Required information Skip to question A die (six faces) has the number 1 painted on two of its faces, the number 2 painted on th

grigory [225]

Answer:

The change to the face 3 affects the value of P(Odd Number)

Step-by-step explanation:

Analysing the question one statement at a time.

Before the face with 3 is loaded to be twice likely to come up.

The sample space is:

$S = \{1,1,2,2,2,3\}$

And the probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{6}$

$P(1) = \frac{1}{3}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{6}$

$P(2) = \frac{1}{2}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{6}$

P(Odd Number) is then calculated as:

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{1}{3} + \frac{1}{6}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{6}$

$P(Odd\ Number) = \frac{3}{6}$

$P(Odd\ Number) = \frac{1}{2}$

After the face with 3 is loaded to be twice likely to come up.

The sample space becomes:

$S = \{1,1,2,2,2,3,3\}$

The probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{7}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{7}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{7}$

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{2}{7} + \frac{1}{7}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{7}$

$P(Odd\ Number) = \frac{3}{7}$

Comparing P(Odd Number) before and after

$P(Odd\ Number) = \frac{1}{2}$ --- Before

$P(Odd\ Number) = \frac{3}{7}$ --- After

<em>We can conclude that the change to the face 3 affects the value of P(Odd Number)</em>

7 0

3 years ago