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Semmy [17]
2 years ago
8

4. Each pail of plaster covers 90 square feet of ceiling. What is the least number of pails of plaster you would need to buy to

cover the ceiling of a square room with walls 14 feet long?
5 pails
6 pails
4 pails
3 pails
Mathematics
2 answers:
KIM [24]2 years ago
8 0

Answer:

3 pails!

Step-by-step explanation:

The area of the ceiling:

A = 14² = 196 ft²

We need plaster to cover 196 ft².

196 : 90 = 2.17778

-lukelaws

hope I helped if I did please mark me brainliest if I got it wrong sorry!

8090 [49]2 years ago
7 0

Answer:

3 pails

Step-by-step explanation:

The square room's base is 14 x 14 = 196

You need to fill the whole room so you might get extra

so... 196 / 90 = 2.177777778

which means you will need  3 and you will have extra

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A player moves a knight from location (3, 2) to (5, 1) on a chessboard. If the bottom-left square is labeled (1, 1), which descr
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7x + 9 = 58<br><br> x/2 - 12 = -14<br><br> -3x + 33 = -12<br><br> 8x + 16 = 8<br><br> 2x - 2 = -18
masha68 [24]

Answer: a) 7        b) -4         c) 15         d) -1        e) -8

<u>Step-by-step explanation:</u>

7x + 9 = 58

<u>      -9 </u>   <u> -9 </u>

7x       =  49

<u>÷7     </u>     <u> ÷7  </u>

  x      =   7

x/2 - 12 =  -14

<u>       +12 </u>   <u>+12 </u>

x/2       =   -2

<u>×2     </u>     <u>  ×2  </u>

  x      =    -4

-3x + 33 =  -12

<u>        -33 </u>   <u> -33 </u>

-3x         =  -45

<u>÷-3     </u>     <u> ÷-3  </u>

  x         =   15

8x + 16 =    8

<u>       -16 </u>   <u> -16 </u>

8x        =   -8

<u>÷8     </u>     <u>  ÷8  </u>

  x      =    -1

2x - 2 = -18

<u>      +2 </u>   <u>+2 </u>

2x       = -16

<u>÷2     </u>    <u> ÷2  </u>

  x      =  -8

7 0
4 years ago
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