Hello,
2x²+x-14=0
Δ=1+4*14*2=113
x=(-1-√113)/4=-2,8839...≈-2.88
or x=(-1+√113)/4=2,40753≈2.41
Answer:
5.x^8.y^3
Step-by-step explanation:
15.x^10.y^5.z^2 ÷ 3.x^2.y^2.z^2
= 15/3. x^(10-2). y^(5-2). z^(2-2)
= 5.x^8.y^3.z^0
= 5.x^8.y^3
Answer:
P ( snowboard I ski) = 0.5714
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is

In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Ski
Event B: Snowboard.
28 out of 120 students ski:
This means that 
16 out of 120 do both:
This means that 
P ( snowboard I ski)

So
P ( snowboard I ski) = 0.5714