for the lines k (x) = (- 9 / 5) x + (5 / 2) and h (x) = (2 / 5) x - (7 / 6), the solution for x will be 5 / 3 and y will be - 1 / 2.
We are given the two lines:
k (x) = (- 9 / 5) x + (5 / 2)
h (x) = (2 / 5) x - (7 / 6)
At the intersection of the two lines, we get that:
(- 9 / 5) x + (5 / 2) = (2 / 5) x - (7 / 6)
(2 / 5) x + (9 / 5) x = (5 / 2) + (7 / 6)
(11 / 5) x = 11 / 3
3 x = 5
x = 5 / 3
y = (2 / 5) (5 / 3) - (7 / 6)
y = 2 / 3 - 7 / 6
y = - 1 / 2
Therefore, we get that, for the lines k (x) = (- 9 / 5) x + (5 / 2) and h (x) = (2 / 5) x - (7 / 6), the solution for x will be 5 / 3 and y will be - 1 / 2.
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I think the answer could be 10 or even 12
The scale for the second values is 56/8 = 7
C = 3 x 7 = 21
C= 21
The first two are equivalent to 15 = k + 13
8 = k + 13 - 7 → ( add 7 to both sides )
8 + 7 = k + 13 ⇒ 15 = k + 13 ' is equivalent '
12 = k + 13 - 3 → ( add 3 to both sides )
12 + 3 = k + 13 ' is equivalent '
