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2 years ago

How do you simplify: 2 radical 50- 3 radical 8

1 answer:

3 0

Let A = <span>2 radical 50- 3 radical 8
</span> radical 50 = sqrt( 2* 25 ) = 5sqrt( 2 )
radical 8 = sqrt(2*4) = 2 sqrt(2)
so
A = 2 radical 50- 3 radical 8 = 10sqrt( 2 ) - 6sqrt( 2 ) = 4sqrt( 2 )
finally

A = 4sqrt( 2 )

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The price of a gallon of gas dropped from the summer high price of $3.50 to the winter low price of $2.87 . By what percentage w

malfutka [58]

Answer:

18%

Step-by-step explanation:

3.50-2.87=0.67

18% of 3.50 is 0.67

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2 years ago

What percent of 126 is 22

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3 years ago

Assume that 13% of people are left-handed. If we select 10 people at random, answer the following questions:

Anastasy [175]

Answer:

0.099, 0.969,0.87,8.3.1.063

Step-by-step explanation:

Let X be the left handed people in the sample of 10 people selected.

X is binomial with n=10 and p = 0.13

a) the probability that there are exactly 3 lefties in the group

= $P(x=3) = 10C3 (0.13)^3 (0.87)^7\\= 0.09945\\=0.099$

b) the probability that there are at least 3 lefties in the group

= $P(X\geq 3) =0.9687\\=0.969$

Now Y number of right handers is binomial with n =10 and p = 0.87

c) the expected number of right-handers in the group.

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d) the standard deviation of the number of right-handers in the group

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5 0

3 years ago

Can you tell me what is 20/10,15/8,and 13/6 as a mixed number

RideAnS [48]

20,10 is 2.
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Glad I could help, and good luck!

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3 years ago

The probability of success is 0.6 for each trial. Find the probability of each:

lapo4ka [179]

Answer:

1. 0.1367

2. 0.0709

3. 0.1766

Step-by-step explanation:

The probability of success is p=0.6, then the probability of a failure is q=1-0.6=0.4.

1. The probability that there are exactly 13 successes in 24 trials is

$C^{24}_{13}p^{13}q^{24-13}=\dfrac{24!}{13!(24-13)!}\cdot (0.6)^{13}\cdot (0.4)^{11}\approx 0.1367$

2. The probability that there are exactly 9 successes in 20 trials is

$C^{20}_{9}p^{9}q^{20-9}=\dfrac{20!}{9!(20-9)!}\cdot (0.6)^{9}\cdot (0.4)^{11}\approx 0.0709$

3. The probability that there are exactly 6 failures in 12 trials is

$C^{12}_{6}q^{6}p^{12-6}=\dfrac{12!}{6!(12-6)!}\cdot (0.4)^{6}\cdot (0.6)^{6}\approx 0.1766$

4 0

3 years ago