Answer:
Step-by-step explanation:
To do this, you must substitute for x in the equation g(x)
Simplified this would be
<h3>
Answer: 2p + 3q</h3>
Work Shown:
log(200) = log(2^3*5^2)
log(200) = log(2^3) + log(5^2)
log(200) = 3*log(2) + 2*log(5)
log(200) = 3*q + 2*p
log(200) = 2p + 3q
The log rules I used were
log(A*B) = log(A)+log(B)
log(A^B) = B*log(A)
Answer:
E. 2 1/2
E. 8.5 cm
C. 6 cm
Step-by-step explanation:
4............................
Scale factor = AE/AC = (4+6)/4 = 10/4 = 2.5
<u>Correct option is</u> E. 2 1/2
5............................
DE = ?
- DE = √AD² - AE² = √15² - 10² = √125 = 5√3 ≈ 8.66
- <em>For measure of AD see next question (6)</em>
<u>Close option is</u> E. 8.5 cm
6............................
AB = ?
- AD/AB = 2.5 <em>the scale factor as per question 4</em>
- (AB + 9)/AB = 2.5
- 2.5*AB = AB + 9
- 1.5*AB = 9
- AB = 9/1.5
- AB = 6 cm
<u>Correct option</u> C. 6 cm
12.5/100
This can be simplified to:
125/1000
1.BD=AC
AC^2=(9^2)+(6^2)-2(9)(6)COS115
AC^2=117-108COS115
AC=√71.358
AC=8.447//