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juin [17]
2 years ago
6

Evaluate the following expression for: x= -2, y=4, z=-3 4(2x+y)-2y+z

Mathematics
1 answer:
otez555 [7]2 years ago
7 0

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\blue\textsf{\textbf{\underline{\underline{Question:-}}}}

Evaluate the expression 4(2x+y)-2y+z for x=-2, y=4 and z=-3

\blue\textsf{\textbf{\underline{\underline{Answer and How to solve:-}}}}

Before inserting the values of the variables, I recommend writing the equation in its simplest form.

First, use the distributive property and distribute 4:-

8x+4y-2y+z

Simplifying,

8x+2y+z

Now that the expression is in its simplest form, we can substitute the variables and simplify the expression.

First, write -2 in lieu of x:-

8(-2)+2y+z

-16+2y+z

Now, write 4 in lieu of y:-

-16+2(4)+z

-16+8+z

-8+z

Final step:-

write -3 in lieu of z:-

-8+(-3)

-8-3

-11

<h3>Good luck.</h3>

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PLEASE HELP!!!!!! the sum of a number times 10 and 15 is at most -17
Brilliant_brown [7]

Let the number = x

Writing the equation you have:

10x + 15 <= -17

Solve for x

Subtract 15 from both sides:

10x <= -32

Divide both sides by 10:

X <= -32/10

Simplify:

X <= -16/5 as a fraction or -3.2 as a decimal

3 0
3 years ago
Solution to this equation -2 = t3
klio [65]

Answer:

Step-by-step explanation:

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-2/3=t

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6 0
2 years ago
What is the coefficient of the x5y5-term in the binomial expansion of (2x – 3y)10? 10C5(2)5(3)5 10C5(2)5(–3)5 –10C5(2)5(–3)5 10C
butalik [34]

ANSWER

10C_5(2)^{5}( - 3)^5

EXPLANATION

The given binomial expansion is:

{(2x - 3y)}^{10}

Compare this to

{(a + b)}^{n}

we have a=2x , b=-3y and n=10

We want to find the coefficient of the term

{x}^{5}  {y}^{5}

This implies that, r=5.

The terms in the expansion can be obtained using

T_{r+1}=nC_ra^{n-r}b^r

We substitute the given values to obtain;

T_{5+1}=10C_5(2x)^{10-5}(  - 3y)^5

T_{6}=10C_5(2x)^{5}(3y)^5

T_{6}=10C_5(2)^{5}( - 3)^5 {x}^{5}  {y}^{5}

Hence the coefficient is;

10C_5(2)^{5}( - 3)^5

5 0
3 years ago
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Answer:

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Step-by-step explanation:

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The answer is C. Seasonal pattern
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