All categories

1 year ago

Why y'all put 1\3 bdhchgf d gchg hello. helo0o elhwl

Mathematics

1 answer:

nydimaria [60]1 year ago

5 0

Answer:

1/3=33.33%?

Step-by-step explanation:

the only math I see is 1/3 and a random 0 near O's

You might be interested in

Let f(x) = 3x + x², find f(4).

xenn [34]

F(4) is equivalent to 28 because when you plug in 4 for the x, you get 28.

4 0

3 years ago

Read 2 more answers

If a = 7, what is the value of the expression 2(a + 8)?

viktelen [127]

Answer:

$2(a + 8) \\ if \: a = 7 \\ 2 \times (7 + 8) \\ 2 \times 15 \\ = 30 \\$

please mark as brainliest

8 0

2 years ago

Read 2 more answers

How many gallons each of 20% alcohol and 10% alcohol should be mixed to obtain 10gal of 11% alcohol?

Scilla [17]

Answer:

20% alcohol = 1 gal

10% alcohol = 9 gal

Step-by-step explanation:

Let

x = 20% alcohol

y = 10% alcohol

x + y = 10 (1)

0.20x + 0.10y = 10*0.11

0.20x + 0.10y = 1.1 (2)

From (1)

x = 10 - y

Substitute x = 10 - y into (2)

0.20x + 0.10y = 1.1

0.20(10 - y) + 0.10y = 1.1

2 - 0.20y + 0.10y = 1.1

- 0.20y + 0.10y = 1.1 - 2

-0.10y = -0.9

y = -0.9/-0.10

y = 9 gal

substitute y = 9 into (1)

x + y = 10

x + 9 = 10

x = 10 - 9

x = 1 gal

20% alcohol = 1 gal

10% alcohol = 9 gal

6 0

2 years ago

McAllister et al. (2012) compared varsity football and hockey players with varsity athletes from noncontact sports to determine

jonny [76]

Answer:

$t _{critical} = 1.760$

t = 2.2450

d. 0.264

Step-by-step explanation:

The null hypothesis is:

$H_o: \mu_1 - \mu_2 = 0$

Alternative hypothesis;

$H_a : \mu_1 - \mu_2 > 0\\$

The pooled variance t-Test would have been determined if the population variance are the same.

$S_p^2 = \dfrac{(n_1-1)S_1^2+(n_2-1)S^2_2}{(n_1-1)+(n_2-1)}$

$S_p^2 = \dfrac{(8-1)2.507^2+(8-1)2.8282^2}{(8-1)+(8-1)}$

$S_p^2 = 7.14$

The t-test statistics can be computed as:

$t= \dfrac{(x_1-x_2)-(\mu_1 - \mu_2)}{\sqrt{Sp^2 ( \dfrac{1}{n} +\dfrac{1}{n_2})}}$

$t= \dfrac{(9-6)-0}{\sqrt{7.14 ( \dfrac{1}{8} +\dfrac{1}{8})}}$

$t= \dfrac{3}{1.336}$

t = 2.2450

Degree of freedom $df = (n_1 -1) + ( n_2 +1 )$

df = (8-1)+(8-1)

df = 7 + 7

df = 14

At df = 14 and ∝ = 0.05;

$t _{critical} = 1.760$

Decision Rule: To reject the null hypothesis if the t-test is greater than the critical value.

Conclusion: We reject $H_o$ and there is sufficient evidence to conclude that the test scores for contact address s less than Noncontact athletes.

To calculate r²

The percentage of the variance is;

$r^2 = \dfrac{t^2}{t^2 + df}$

$r^2 = \dfrac{2.2450^2}{2.2450^2 + 14}$

$r^2 = \dfrac{5.040025}{5.040025+ 14}$

$r^2 = 0.2647$

7 0

2 years ago

Do the ratios 1:5 and 3:4 form a proportion?

bagirrra123 [75]

Answer

Step-by-step explanation:

3 0

2 years ago