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Ostrovityanka [42]
2 years ago
7

Hazel's backyard deck cost $76.13 per square yard to build. The deck is 7 yards wide and 11 yards long. How much did it cost to

build the deck?
Mathematics
1 answer:
horsena [70]2 years ago
4 0
If I’m not mistaken it should be $5,862.1
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Need help please.........................
Archy [21]

Answer:

16t^{2} + 2t - 6

Step-by-step explanation:

(12t^{2}  + 5t -y) - (-4t^{2} + 3t -1)

simplify

12t^{2} + 5t -7 +4t^{2} -3t +1

combine like terms

16t^{2} + 2t - 6

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2 years ago
Five people went to the concert for $227.50. If tickets are all the same price, how many people could go for $546?
Ilya [14]
ANSWER: 12 people can go
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2 years ago
Determine whether the geometric series is convergent or divergent. 9 + 8 + 64/9 + 512/81 + ..... If it is convergent, find its s
Westkost [7]

Answer:

Convergent; 81

Step-by-step explanation:

r = term2/term1 = 8/9

8/9 < 1 so convergent

Sum = 9/(1 - 8/9)

= 9/(1/9) = 81

3 0
2 years ago
If 12 less than 4 times a number is 8, the number is 5. What difference sentence where the unknown number is also 5?
Gnesinka [82]
Sent a picture of the solution to the problem (s).

8 0
3 years ago
In Vancouver, British Columbia, the probability of rain during a winter day is 0.42, for a spring day is 0.23, for a summer day
nadezda [96]

Answer:

31.82% probability that this day would be a winter day

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening

In this question:

Event A: Rain

Event B: Winter day

Probability of rain:

0.42 of 0.25(winter), 0.23 of 0.25(spring), 0.16 of 0.25(summer) or 0.51 of 0.25(fall).

So

P(A) = 0.42*0.25 + 0.23*0.25 + 0.16*0.25 + 0.51*0.25 = 0.33

Intersection:

Rain on a winter day, which is 0.42 of 0.25. So

P(A \cap B) = 0.42*0.25 = 0.105

If you were told that on a particular day it was raining in Vancouver, what would be the probability that this day would be a winter day?

P(B|A) = \frac{0.105}{0.33} = 0.3182

31.82% probability that this day would be a winter day

6 0
3 years ago
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