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Ann [662]
3 years ago
9

QUESTION 8 Write an inequality to represent the real-world problem. Then explain how you created the inequality. You have caviti

es and you are looking for a cheaper dentist. Dentist A costs $50 for the visit and $20 per cavity. Dentist B costs $70 for the visit and $5 per cavity. When would Dentist B be cheaper than Dentist A?
Mathematics
1 answer:
Marizza181 [45]3 years ago
6 0

Answer:

I can give you alittle head start. I hope it kinda helps.

Step-by-step explanation:

Dentist A: 50 + 20x

Dentist B: 70 + 5x

It cost 20 more dollars for the visit and 15 dollars less for each cavaty at Dentist B.

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Answer:

t=\frac{5.25-4.73}{\frac{3.98}{\sqrt{54}}}=0.9601  

P-value  

First we find the degrees of freedom given by:

df = n-1= 54-1=53

Since is a two-sided test the p value would be:  

p_v =2*P(t_{53}>0.9601)=0.3414  

Step-by-step explanation:

Data given and notation  

\bar X=5.25 represent the sample mean

s=3.98 represent the sample standard deviation

n=54 sample size  

\mu_o =4.73 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean differs from 4.73, the system of hypothesis would be:  

Null hypothesis:\mu =4.73  

Alternative hypothesis:\mu \neq 4.73  

Since we know don't the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{5.25-4.73}{\frac{3.98}{\sqrt{54}}}=0.9601  

P-value  

First we find the degrees of freedom given by:

df = n-1= 54-1=53

Since is a two-sided test the p value would be:  

p_v =2*P(t_{53}>0.9601)=0.3414  

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3 years ago
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