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abruzzese [7]
2 years ago
11

Identify the type of display that would be most appropriate for the description of the given data set. The number of pets in eac

h student's household.
Mathematics
1 answer:
Talja [164]2 years ago
4 0

send a screen shot of the whole question so i can help becuase there is no data here to even help you with

Step-by-step explanation:

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What is the measure of angle BCD?<br><br><br><br> 98<br> 110<br> 82<br> 70
Dafna11 [192]

Answer:

82

Step-by-step explanation:

opposite angles in a cyclic quadrilateral are supplimentary

4 0
2 years ago
What is the sum of the geometric series
lbvjy [14]
If S denotes the sum of the first n terms of a geometric series with first term a and common ratio r, then

S=a+ar+ar^2+\cdots+ar^{n-3}+ar^{n-2}+ar^{n-1}
rS=ar+ar^2+ar^3+\cdots+ar^{n-2}+ar^{n-1}+ar^n
\implies S-rS=a+(ar-ar)+(ar^2-ar^2)+\cdots+(ar^{n-1}-ar^{n-1})-ar^n
\implies (1-r)S=a(1-r^n)
\implies S=a=\dfrac{1-r^n}{1-r}

Using summation notation, you have

S=\displaystyle\sum_{x=1}^nar^{x-1}=\sum_{x=0}^{n-1}ar^x=a\dfrac{1-r^n}{1-r}

In this case, you have a=2, r=\dfrac12, and n=16. So the value of the sum is

\displaystyle\sum_{x=0}^{15}2\left(\frac14\right)^x=2\dfrac{1-\left(\frac14\right)^{16}}{1-\frac14}\approx2.67

Rounded to the nearest whole number, the answer would be 3.
4 0
3 years ago
Read 2 more answers
Help needed ASAP it’s geometry
ivanzaharov [21]

Answer:

<h2>           32</h2>

Step-by-step explanation:

\tan(29.4^o)=\dfrac{?}{56.8}\\\\\tan(29.4^o)\times56.8=?\\\\?\approx0,563471\times56.8\approx32

5 0
3 years ago
To join a local square dancing group, Jan has to pay a $100 sign-up fee plus $25 dollars per month. Write an equation for the co
NemiM [27]

Answer:

y = 25x+100

Step-by-step explanation: You are paying 25$ times how many months he stayed there, plus a 100 dollar sign up fee, so y = 25 dollars per month, plus 100 dollars.



4 0
3 years ago
Simplify this radical <br> 3√12<br> and this one <br> 2√(48x^3 )
MakcuM [25]
For number one you should get 6√3





4 0
3 years ago
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