All categories

3 years ago

(4y 2 – 5y) + (3y – 7y 2) – (2y 2 + 6y – 5) Simplify.

1 answer:

4 0

Equation at the end of step 1 : (((4•(y2))-5y)+(3y-(7•(y2))))-((2y2+6y)-5) Step 2 :Equation at the end of step 2 : (((4•(y2))-5y)+(3y-7y2))-(2y2+6y-5) Step 3 :Equation at the end of step 3 : ((22y2 - 5y) + (3y - 7y2)) - (2y2 + 6y - 5) Step 4 : Step 5 :Pulling out like terms :

5.1 Pull out like factors :

 -5y2 - 8y + 5 = -1 • (5y2 + 8y - 5)

I hope tht help

You might be interested in

Find the mean. Z-score = -1.4 Standard Deviation: 7 x = 20

Umnica [9.8K]

Answer:

9.6

Step-by-step explanation:

8 0

3 years ago

Which shows the integers in order.

Igoryamba

The answer A shows the integers from greatest to least

5 0

3 years ago

Read 2 more answers

Can someone explain the steps to finding the perimeter of a semi-circle? I didn't really understand it during class. Thanks

andriy [413]

We know that the perimeter of a cylinder is 2πr we will find it as we do always. The perimeter will be :
2 pi r
= 2 pi * 20
= 40 pi
Because it says rounded to the nearest tenth the answer will be : 125.6 cm^3
Because we have a half of a cylinder we will just divide the answer we got by 2:
125.6cm^3 /2 =62.8
The answer is 62.8 cm^3

6 0

2 years ago

The lateral surface area S of a right circular cone is given by (equation given below). What radius should be used to produce a

Dima020 [189]

Given:
Lateral Area = π * r * (√h² + r²)

Lateral Area = 100 in² ; height = 5 in

I find it hard to derive the formula of r because of the radical sign. So, I'll just plug each radius to the formula to check confirm the given lateral area.

a) r = 1.52138 ⇒ LA = 24.98
b) r = 4.658 ⇒ LA = 100
c) r = 78 ⇒ LA = 19152.68
d) r = 6.7432 ⇒ LA = 177.84

The radius is B.) r = 4.658 inches

7 0

2 years ago

Read 2 more answers

What is the best approximation of the projection of (5,-1) onto (2,6)?

Hatshy [7]

Answer:

Hence, the scalar projection of $\vec a$ onto $\vec b$ = $\frac{\sqrt{10} }{5}$ , and the vector projection of $\vec a$ onto $\vec b$ = $\frac{1}{5} \hat i+\frac{3}{5} \hat j$ .

Step-by-step explanation:

We have given two points $(5, -1)$ and $(2, 6)$ .

Let, $\vec a=5\hat {i}-\hat {j}$ and $\vec b= 2\hat {i}+6\hat{j}$ .

and we have calculate the projection of $\vec a$ onto $\vec b$ .

Now,

For the calculation of projection, first we need to calculate the dot product of $\vec a$ and $\vec b$ .

$\vec a.\vec b=(5\hat {i}-\hat{j}).(2\hat{i}+6\hat{j})$

$=10-6$

$=4$

then, we have to calculate the magnitude of $\vec b$ .

$\mid {\vec {b}}\mid$ = $\sqrt{2^{2}+6^{2} }$ = $\sqrt{40}$ = $2\sqrt{10}$ .

Now, the scalar projection of $\vec a$ onto $\vec b$ = $\frac{\vec a.\vec b}{\mid b\mid}$

= $\frac{4}{2\sqrt{10} }$ $\frac{2}{\sqrt{10} } \times\frac{\sqrt{10} }{\sqrt{10} } =\frac{2\sqrt{10} }{10} = \frac{\sqrt{10} }{5}$

and the vector projection of $\vec a$ onto $\vec b$ = $\frac{\vec a. \vec b}{\mid\vec b \mid^{2} } . \vec b$

= $\frac{4}{40} . (2\hat i+ 6\hat j)$

= $\frac{1}{5} \hat i+\frac{3}{5} \hat j$

Hence, the scalar projection of $\vec a$ onto $\vec b$ = $\frac{\sqrt{10} }{5}$ , and the vector projection of $\vec a$ onto $\vec b$ = $\frac{1}{5} \hat i+\frac{3}{5} \hat j$ .

6 0

3 years ago