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s2008m [1.1K]
2 years ago
7

You invest $10,000 in an account with 1.250% interest, compounded

Mathematics
1 answer:
Luden [163]2 years ago
5 0

Answer:

Growth of $10,000 at 2% Interest

Year Amount

0 $10,000

1 $10,200

2 $10,404

3 $10,612

4 $10,824

5 $11,041

6 $11,262

7 $11,487

8 $11,717

9 $11,951

10 $12,190

$10,000 for 10 Years by Interest Rate

Rate Amount

1% $11,046

2% $12,190

3% $13,439

4% $14,802

5% $16,289

6% $17,908

8% $21,589

10% $25,937

12% $31,058

15% $40,456

20% $61,917

Step-by-step explanation:

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Add these fractions 5/7 + 2/7 is it to 3 or
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Answer:

1

Step-by-step explanation:

5/7+2/7 add the numerator to equal 7/7 simplify to 1/1 equals 1

3 0
2 years ago
Read 2 more answers
1.) Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth .x squared minus 21 x equals n
Andrew [12]
Part 1
We are given x^2-21x=-4x. This can be rewritten as x^2-18x=0.
Therefore, a=1, b=-18, c=0.
Using the quadratic formula
     x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}=\frac{-\left(-18\right)\pm \sqrt{\left(-18\right)^2-4\left(1\right)\left(0\right)}}{2\left(1\right)}
     x=\frac{18\pm 18}{2}

The values of x are
     x_1=\frac{18-18}{2}=0
     x_2=\frac{18+18}{2}=18

Part 2
Since the values of y change drastically for every equal interval of x, the function cannot be linear. Therefore, the kind of function that best suits the given pairs is a quadratic function. 

Part 3.
The first equation is y=x^2+2.
The second equation is y=3x+20.

We have 
     x^2+2=3x+20
     x^2-3x-18=0
Factoring, we have 
     \left(x-6\right)\left(x+3\right)=0
Equating both factors to zero.
     x_1-6=0\rightarrow x_1=6
     x_2+3=0\rightarrow x_2=-3

When the value of x is 6, the value of y is 
     y=3\left(6\right)+20=38

When the value of x is -3, the value of y is 
     y=3\left(-3\right)+20=11

Therefore, the solutions are (6,38) or (-3,11)
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Step-by-step explanation:

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