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Simora [160]
2 years ago
14

I need help with this question

Mathematics
1 answer:
pav-90 [236]2 years ago
8 0

Answer:

Pearson Math Book nice.

Step-by-step explanation:

I think the 11 ounces because thats the accurate one and determine if its regular or rush. Hope that helps.

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Helos answee please im dumb asap​
exis [7]

Answer:

114

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What must be added to x² + 6x²-x+ 5 to make it exact divisible by (x + 3)​
maxonik [38]

Let f(x) = x² + 6x²-x+ 5 then ,

number to be added be P

then,

f(x) = x² + 6x²-x+ 5 +P

According to the qn,

(x+3) is exactly divisible by zero then,

R=0

comparing .. we get a= -3

now by remainder theorm

R=f(a)

0=f(-3)

0=(-3)² + 6(-3)²-(-3)+ 5 + P

0= 9 + 54 + 3 + 5 + P

-71=P

therefore, -71 should be added.

Hope you understand

4 0
2 years ago
How do u write 4408730 in expanded form?
STALIN [3.7K]
Do you need the expanded notation form, or expanded factor form?
5 0
3 years ago
Two cards are drawn at random without replacement from a deck of 52 playing cards. If the first card chosen is a King, what is t
gulaghasi [49]

Answer:

p=0.05882

Step-by-step explanation:

Probability is the likelihood of an event occurring.

-A standard deck of cards has 4 kings.

#After one card is removed, 51 remains of which 3 are kings:

P(king)=\frac{3}{51}\\\\=0.05882

Hence, the probability that the second card is king is 0.05882

3 0
3 years ago
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Which set of ordered pairs could represent a function? (2, 3), (2, 2), (2, 4), (2, 9), (2, –2) (1, 5), (2, 6), (1, 6), (4, 5), (
Ratling [72]

Given:

The set of ordered pairs in the options:

(a) (2, 3), (2, 2), (2, 4), (2, 9), (2, –2)

(b) (1, 5), (2, 6), (1, 6), (4, 5), (1, 4)

(c) (1, 0), (2, 0), (1, 3), (4, 3), (5, 7)

(d) (5, 1), (7, 3), (9, 5), (11, 7), (13, 9)

To find:

The set of ordered pairs that could represent a function.

Solution:

A set of ordered pairs represent a function, if there exist unique output (y-value) for each input (x-value).

In option (a) we have, five output values y=3,2,4,9,-2 for single input x=2. So, it is not a function.

In option (b) we have, three output values y=5,6,4 for single input x=1. So, it is not a function.

In option (c) we have, two output values y=0,3 for single input x=1. So, it is not a function.

In option (d), all inputs has unique output.

Therefore, the correct option is (d).

4 0
3 years ago
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