In triangle ABC, what is the measure of b if a = 51, c = 38, and B = 11°?

Mathematics

2 answers:

diamong [38]2 years ago

7 0

Answer:

see photo attached for your reference.

Step-by-step explanation:

15.50 (to the nearest hundredth)

suter [353]2 years ago

7 0

Answer:

The area of a triangle is the region enclosed between the sides of the triangle. Area of ΔABC = 1/2 × Base × Height. Let us know the basics of the area of a triangle. If ABC is an equilateral triangle, Area of ΔABC = (√3/4)a2 where a is the length of a side of the equilateral triangle.

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Find the area or this triangle

Arlecino [84]

Answer:

Area of triangle = 15 square units

Step-by-step explanation:

We need to find area of the triangle, given the vertices:

A=(4,0)

B=(1,5)

C=(7,5)

The formula used is: $Area\:of\:triangle=\frac{1}{2}(x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2))$

We have: $x_1 =4, y_1 =0, x_2 =1, y_2=5, x_3=7 , y_3=5$

Putting values and finding area

$Area\:of\:triangle=\frac{1}{2}(x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2))\\Area\:of\:triangle=\frac{1}{2}(4(5-5)+1(5-0)+7(0-5))\\Area\:of\:triangle=\frac{1}{2}(4(0)+1(5)+7(-5))\\Area\:of\:triangle=\frac{1}{2}(0+5-35)\\Area\:of\:triangle=\frac{1}{2}(-30)\\Area\:of\:triangle=-15$