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Irina18 [472]
3 years ago
9

Solve (+)127-9 = (2) (+2) for x

Mathematics
1 answer:
Aleksandr [31]3 years ago
8 0

Answer: 118=4

Explanation

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Please answer this is only algebra 1
Alexeev081 [22]

The numeric values for the given functions are as follows:

  • f(1/3) = 1/9.
  • g(4) = 8.
  • g(-3) = -6.

<h3>How to find the numeric value of a function or of an expression at a given point?</h3>

To find the numeric value of a function at x = a, we replace each instance of the variable, usually x, in the function by the desired value of a.

Function f(x) is defined by:

f(x) = x².

For the numeric value at x = 1/3, we replace the lone instance of x by 1/3, hence:

f(1/3) = (1/3)² = 1/9.

Function g(x) is defined by:

g(x) = 2x.

For the numeric value at x = 4, we replace the lone instance of x by 4, hence:

g(4) = 2(4) = 8.

For the numeric value at x = -3, we replace the lone instance of x by -3, hence:

g(-3) = 2(-3) = -6.

More can be learned about the numeric values of a function at brainly.com/question/28367050

#SPJ1

6 0
1 year ago
Please help me urgent
lana [24]

Answer:

19

explanation

not sure but

just count the whole blocks and

After you have counted u take 2 half blocks and

make a whole

7 0
2 years ago
When Lena went to her friend's sleepover on Friday night, the temperature was – 7°F. By the next morning, the temperature had ri
BartSMP [9]

Answer:

The answer is 6.

The change in temperature during the sleep over was 6°F.

Step-by-step explanation:

-1-(-7) = -1 + 7

=6

7 0
3 years ago
Find the lowest common multiple (LCM) for 5 and 7
Paha777 [63]
The lcm of 5 and 7 is 35
8 0
3 years ago
Read 2 more answers
6th square root of 125x^3y^9z^6
Slav-nsk [51]
 Irrational numbers are those numbers whose denominators and in square root forms. We can express the numbers in lowest terms by taking out divisible perfect square numbers out of the square root sign. In this case, the rules applicable is that the simplest forms are those forms in which the variables degree is less than to the nth root. The numbers inside the roots should be divisible to the nth power of a number. 
In this case, 125 is not divisible than any 6th root. The only other variable that can be 6th root is y^9 and x^6. hence the answer is 
yz 6th root of (125x^3y^3)

8 0
3 years ago
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