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2 years ago

Solve triangle d, angle F and angle E when e=10, d=16.4, f=13, angle D=50

Mathematics

1 answer:

vodomira [7]2 years ago

5 0

Answer:

P=a+b+c

the given triangle using the Law of Sines. Round lengths to the nearest tenth and angle measurements to the nearest degree.

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3 years ago

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Please help me with this question

san4es73 [151]

Step-by-step explanation:

Given: $f'(x) = x^2e^{2x^3}$ and $f(0) = 0$

We can solve for f(x) by writing

$\displaystyle f(x) = \int f'(x)dx=\int x^2e^{2x^3}dx$

Let $u = 2x^3$

$\:\:\:\:du=6x^2dx$

Then

$\displaystyle f(x) = \int x^2e^{2x^3}dx = \dfrac{1}{6}\int e^u du$

$\displaystyle \:\:\:\:\:\:\:=\frac{1}{6}e^{2x^3} + k$

We know that f(0) = 0 so we can find the value for k:

$f(0) = \frac{1}{6}(1) + k \Rightarrow k = -\frac{1}{6}$

Therefore,

$\displaystyle f(x) = \frac{1}{6} \left(e^{2x^3} - 1 \right)$

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2 years ago

Justin divided a number by 4 and got remainder 7.

Katyanochek1 [597]

Answer:

There is not enough information for this problem, can you provide more information?

Step-by-step explanation:

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2 years ago

the width of a rectangle is 6 2/3. the length of the rectangle is twice its width. what is the perimeter of the rectangle?

melamori03 [73]

Answer:

The perimeter is 40 units.

Step-by-step explanation:

First multiply the width by 2

6 2/3 * 2 = 13 1/3

Now take two 6 2/3 and two 13 1/3 an add them

6 2/3 + 6 2/3 + 13 1/3 + 13 1/3

= 40

Hope this helps you :3

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2 years ago

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