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diamong [38]
3 years ago
7

Find the area of the shaded region. Round your answer to the nearest hundredth. Help pls

Mathematics
2 answers:
Sophie [7]3 years ago
8 0
The other person is correct I just wanted to let you know
slavikrds [6]3 years ago
4 0

Answer:

Step-by-step explanation:

area of square=8²=64  m²

radius of each circular arc at the corner=8/2=4 m

area of  four circular arcs=4×1/4 ×π×4²=16  π m²

area of shaded region=64-16π=16(4-π)≈13.73 m²

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(Please answer before 5:15 P.M tonight)
taurus [48]

The scale factor of dilation from ABC to A^{1} B^{1} C^{1} is 0.333.

Step-by-step explanation:

Step 1:

First, we plot the coordinates of both triangles.

The coordinates of the triangle A^{1} B^{1} C^{1} are as follows;

A^{1} = (2, 3), B^{1} = (2, 1), and C^{1} = (3, 1).

The coordinates of triangle ABC are;

A = (4, 9), B = (4, 3), and C = (7, 3).

Step 2;

Next, we need to find the distances between at least two coordinates for both triangles.

The distances between vertical lines are found by calculating the difference in y values while for horizontal lines, the distances are found by calculating the difference between the x values.

The distance of A^{1} B^{1} = 3-1=2, the distance of B^{1} C^{1} = 3-2=1.

The distance of AB =9-3=6, the distance of BC = 7-4=3.

Step 3;

To calculate the scale factor, we divide the measurement after scaling by the same measurement before scaling.

In this case, it is the length of the AB.

So The scale factor for AB = \frac{2}{6} = \frac{1}{3} = 0.333.

The scale factor for BC = \frac{1}{3} = 0.333.

7 0
3 years ago
****BRAINLIEST GOES TO THE FIRST CORRECT ANSWER****
erik [133]
Given
Segment Addition Postulate
Transitive Property of Equality
4 0
3 years ago
What is the solution to this inequality?<br> -4X &gt; 500
Tcecarenko [31]

Answer: x < -125

Step-by-step explanation:

-4x / (-4) < 500 / (-4)

x < -125

7 0
3 years ago
Line RS intersects triangle BCD at two points and is parallel to segment DC. Triangle B C D is cut by line R S. Line R S goes th
Svetlanka [38]

Answer:

The correct options are;

1) ΔBCD is similar to ΔBSR

2) BR/RD = BS/SC

3) (BR)(SC) = (RD)(BS)

Step-by-step explanation:

1) Given that RS is parallel to DC, we have;

∠BDC = ∠BRS (Angles on the same side of transversal)

Similarly;

∠BCD = ∠BSR (Angles on the same side of transversal)

∠CBD = ∠CBD = (Reflexive property)

Therefore;

ΔBCD ~ ΔBSR Angle, Angle Angle (AAA) rule of congruency

2) Whereby  ΔBCD ~ ΔBSR, we therefore have;

BC/BS = BD/BR → (BS + SC)/BS = (BR + RD)/BR = 1 + SC/BS = RD/BR + 1

1 + SC/BS = 1 + RD/BR = SC/BS = 1 + BR/RD - 1

SC/BS = RD/BR

Inverting both sides

BR/RD = BS/SC

3) From BR/RD = BS/SC the above we have by cross multiplication;

BR/RD = BS/SC gives;

BR × SC = RD × BR → (BR)(SC) = (RD)(BR).

7 0
2 years ago
Mandy emptied the bags and put the candy into equal groups.How many candies were in each group?
alexira [117]

Answer:

25

Step-by-step explanation:

40+76+84 = 200.

200 ÷ 8 = 25

Answer: 25.

3 0
2 years ago
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