The equation, in slope-intercept form, of the line that is parallel to the given line and passes through the point (0, 12) is y = -5x + 1
<h3>Equation of a line</h3>
A line is the distance between two points
Given the equation of a line expressed as 10x + 2y = -2. Determine the slope
2y = -10x -2
y = -5x - 1
Slope of the line is -5
The equation of a line in point-slope form is y - y1 = m(x-x1)
Substitute the point and the slope of the parallel line
y - 12 = -5(x - 0)
y - 12 = -5x
y = -5x + 12
Hence the equation, in slope-intercept form, of the line that is parallel to the given line and passes through the point (0, 12) is y = -5x + 12
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Answer:
x^5y^5
Step-by-step explanation:
<em>here's</em><em> your</em><em> solution</em>
=> if base are same then power get added in multiplication
=> so, x^2 * y^4 * x^3 * y^1
=> x^2 * x^3 * y^4 * y^1
=> x^5*y^5
hope it helps
I believe the answer is false
The answers are...
x=7
y=2