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Vikentia [17]
3 years ago
14

Using the data below, what is the equation for the line of best fit? Remember, put your answer in y = ax + b form and round any

decimals to three places.
Patient Calories Wt. loss/week lbs.
1 1500 2
2 1200 3
3 1800 1
4 2100 .5
5 2400 .75
6 1800 1
7 1200 5
8 2100 1
9 2400 .5
10 1500 2
Mathematics
1 answer:
ratelena [41]3 years ago
5 0
If we fit the data as calories as a function of wt loss/week, we need to arrange the data first from lowest to highest wt loss/week lbs and calories. Then, the set of points can be plotted in a graph and a graphical method of line fitting can be used. Curve fitting programs (which are also in the calculator) can be used. The result is:
y = -266.5741x + 2246.5116

The value of R² is 0.7109. The fit is not very good since R² is quite far from 0.99.
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(Y-1/4)-(y-4/5)=(y+4/10)-1
Arte-miy333 [17]

Answer:

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
The Student Monitor surveys 1200 undergraduates from 100 colleges semiannually to understand trends among college students. Rece
nlexa [21]

Answer:

A sample size of 385 is needed.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

You feel that a reasonable estimate of the standard deviation is 10.0 hours.

This means that \sigma = 10

What sample size is needed so that the expected margin of error of your estimate is not larger than one hour for 95% confidence?

A sample size of n is needed. n is found when M = 1. So

M = z\frac{\sigma}{\sqrt{n}}

1 = 1.96\frac{10}{\sqrt{n}}

\sqrt{n} = 1.96*10

(\sqrt{n})^2 = (1.96*10)^2

n = 384.16

Rounding up:

A sample size of 385 is needed.

7 0
3 years ago
Complete the solution of the equation. fine the value of y <br><br> 9x+7y=-12
dimaraw [331]

Answer:

y=-12/7 - 9x/7

that is the answer

8 0
3 years ago
Yes this is apparently a math equation. Fake answers will be deleted
jeka57 [31]

Answer:

-1 +1 = 0

Step-by-step explanation:

Therefore no charge

4 0
3 years ago
Read 2 more answers
In Triangle XYZ, measure of angle X = 49° , XY = 18°, and
marissa [1.9K]

Answer:

There are two choices for angle Y: Y \approx 54.987^{\circ} for XZ \approx 15.193, Y \approx 27.008^{\circ} for XZ \approx 8.424.

Step-by-step explanation:

There are mistakes in the statement, correct form is now described:

<em>In triangle XYZ, measure of angle X = 49°, XY = 18 and YZ = 14. Find the measure of angle Y:</em>

The line segment XY is opposite to angle Z and the line segment YZ is opposite to angle X. We can determine the length of the line segment XZ by the Law of Cosine:

YZ^{2} = XZ^{2} + XY^{2} -2\cdot XY\cdot XZ \cdot \cos X (1)

If we know that X = 49^{\circ}, XY = 18 and YZ = 14, then we have the following second order polynomial:

14^{2} = XZ^{2} + 18^{2} - 2\cdot (18)\cdot XZ\cdot \cos 49^{\circ}

XZ^{2}-23.618\cdot XZ +128 = 0 (2)

By the Quadratic Formula we have the following result:

XZ \approx 15.193\,\lor\,XZ \approx 8.424

There are two possible triangles, we can determine the value of angle Y for each by the Law of Cosine again:

XZ^{2} = XY^{2} + YZ^{2} - 2\cdot XY \cdot YZ \cdot \cos Y

\cos Y = \frac{XY^{2}+YZ^{2}-XZ^{2}}{2\cdot XY\cdot YZ}

Y = \cos ^{-1}\left(\frac{XY^{2}+YZ^{2}-XZ^{2}}{2\cdot XY\cdot YZ} \right)

1) XZ \approx 15.193

Y = \cos^{-1}\left[\frac{18^{2}+14^{2}-15.193^{2}}{2\cdot (18)\cdot (14)} \right]

Y \approx 54.987^{\circ}

2) XZ \approx 8.424

Y = \cos^{-1}\left[\frac{18^{2}+14^{2}-8.424^{2}}{2\cdot (18)\cdot (14)} \right]

Y \approx 27.008^{\circ}

There are two choices for angle Y: Y \approx 54.987^{\circ} for XZ \approx 15.193, Y \approx 27.008^{\circ} for XZ \approx 8.424.

6 0
3 years ago
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