Hello from MrBillDoesMath!
Answer:
5, 10, 0
Discussion:
Let "f" be the first number. Then the questions tells us that
f + 2f + (f-5) = 15 =>
f + 2f + f - 5 = 15 => add 5 to both sides
4f = 5+ 15 = 20 => divide both sides by 4
f = 20/4 = 5
The numbers as
f: 5
2f: 10
(f-5): 0
Thank you,
MrB
Answer:
i honestly dont know its tooooo hard
Step-by-step explanation:
Assuming it is a Obtuse Scalene Triangle
Side a = 6
Side b = 15
Side c = 13.0767 = 3√19
Answer:
80 m^2
Step-by-step explanation:
The formula is lwh/3. 5*6*8=240 240/3=80
For cos(2x) * (2cos(x) + 1) = 0, use the double angle identity for cos(2x), which is cos^2 x - sin^2 x = cos^2 x - (1-cos^2) = 2cos^2 x - 1.
So we have (2cos^2 x - 1)(2cos x + 1) = 0. So 2cos^2 x -1 = 0 or x = 0 and 2pi.
For 2sec^2 x + tan^2 x - 3 = 0, use the identity sec^2 x = tan^2 x + 1, so we have
2(tan^2 x + 1) + tan^2 x - 3 = 0 or
<span>2tan^2 x + tan^2 x - 1 = 0 or
</span>3 tan^2 x = 1.
So x = pi/2, pi/2 + pi = 3pi/2.