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3 years ago

Find the total cost of producing 5 camera cases.

Mathematics

2 answers:

Aleksandr-060686 [28]3 years ago

8 0

Answer: c(x) = 7x² - 3b + 5

Step-by-step explanation:

c(x), making x camera cases is a quadratic function in terms of x:

c(x) = ax²+bx+c

c(2) = a2²+b.2+c = 27

c(4) = a4²+b.4+c = 105

c(10) = a10²+b.10+c = 675

4a+2b+c = 27

16a+4b+c = 105

100a+10b+c = 675

c = 27 - 4a - 2b

16a+4b+27-4a-2b = 105

100a+10b+27-4a-2b = 675

12a+2b = 78 (x-4)

96a+8b = 648

-48a - 8b = -312

96a + 8b = 648

48a = 336

a = 7

12.7+2b = 78

84 + 2b = 78

2b = -6

b = -3

c = 27 - 4.7 - 2.(-3) = 27 - 28 + 6 = 5

c(x) = 7x² - 3b + 5

svet-max [94.6K]3 years ago

7 0

We can translate the given problem into a table containing the data expressed as
x c(x) ($)2 274 10510 675
to find the total cost of producing 5 cases, we plot first the data and find the equation. The equation is c(x) = 7x2 - 3x + 5. when x is equal to 5, then c(x) is equal to $165

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Solve the following inequality algebraically. ∣x+7∣≤8

AlekseyPX

Answer:

x ≤ 1 and x ≥ −15

Step-by-step explanation:

Solving Absolute Value

We know that x + 7 ≤ 8 or x + 7 ≥ -8

Condition 1:

Step 1: Subtract 7 from both sides.

$x + 7 - 7\leq 8 - 7$
$x\leq 1$

Condition 2:

Step 1: Subtract 7 from both sides.

$x + 7 - 7\geq -8 - 7$
$x\geq -15$

Therefore, the answer is x ≤ 1 and x ≥ -15.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

4 0

3 years ago

What is the answer with work please

frozen [14]

For 12, the answer would be Y is greater than or equal to 8. If you subtract 193 from both sides of the inequality, you are left with y and 201-193=8. So the overall inequality would look like y>=8. Therefore, you would shade from 8, and everything greater than 8, with a closed circle.

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3 years ago

23/7y state restrictions

qwelly [4]

The restrictions on the variable of the given rational fraction is y ≠ 0.

<h3>The types of numbers.</h3>

In Mathematics, there are six (6) common types of numbers and these include the following:

Natural (counting) numbers: these include 1, 2, 3, 4, 5, 6, .....114, ....560.

Whole numbers: these comprises all natural numbers and 0.

Integers: these are whole numbers that may either be positive, negative, or zero such as ....-560, ...... -114, ..... -4, -3, -2, -1, 0, 1, 2, 3, 4, .....114, ....560.

Irrational numbers: these comprises non-terminating or non-repeating decimals.

Real numbers: these comprises both rational numbers and irrational numbers.

Rational numbers: these comprises fractions, integers, and terminating (repeating) decimals such as ....-560, ...... -114, ..... -4, -3, -2, -1, -1/2, 0, 1, 1/2, 2, 3, 4, .....114, ....560.

This ultimately implies that, a rational fraction simply comprises a real number and it can be defined as a quotient which consist of two integers x and y.

<h3>What are restrictions?</h3>

In Mathematics, restrictions can be defined as all the real numbers that are not part of the domain because they produces a value of 0 in the denominator of a rational fraction.

In order to determine the restrictions for this rational fraction, we would equate the denominator to 0 and then solve:

23/7y;

7y = 0

y = 0/7

y ≠ 0.

Read more on restrictions here: brainly.com/question/10957518

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Complete Question:

State any restrictions on the variables 23/7y

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What is the prime factorization of 225 in exponent form

weqwewe [10]

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