Find the total cost of producing 5 camera cases.
2 answers:
Answer: c(x) = 7x² - 3b + 5
Step-by-step explanation:
c(x), making x camera cases is a quadratic function in terms of x:
c(x) = ax²+bx+c
c(2) = a2²+b.2+c = 27
c(4) = a4²+b.4+c = 105
c(10) = a10²+b.10+c = 675
4a+2b+c = 27
16a+4b+c = 105
100a+10b+c = 675
c = 27 - 4a - 2b
16a+4b+27-4a-2b = 105
100a+10b+27-4a-2b = 675
12a+2b = 78 (x-4)
96a+8b = 648
-48a - 8b = -312
96a + 8b = 648
48a = 336
a = 7
12.7+2b = 78
84 + 2b = 78
2b = -6
b = -3
c = 27 - 4.7 - 2.(-3) = 27 - 28 + 6 = 5
c(x) = 7x² - 3b + 5
We can translate the given problem into a table containing the data expressed as x c(x) ($)2 274 10510 675 to find the total cost of producing 5 cases, we plot first the data and find the equation. The equation is c(x) = 7x2 - 3x + 5. when x is equal to 5, then c(x) is equal to $165
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