All categories

1 year ago

Choose the function that represents the data in the table.

Mathematics

1 answer:

viva [34]1 year ago

4 0

$y = 2 {x}^{2} - 3$

$\huge\underline\mathtt\colorbox{cyan}{Explanation thing:}$

Using hit and trial, you van find it pretty easily-

Putting x=0, we get y=-3
Putting x=1, we get y=-1
Putting x=2, we get y=5

You can try it for yourself as well, for me, I couldn't find any other option appropriate.

You might be interested in

Which expression could be modeled by decimal grid?

faust18 [17]

Answer:

D) 0.80×0.40 so the answer is D

7 0

3 years ago

A worker in a silver mine descends 60 feet. Use an integer to represent the change in the worker's position.

iogann1982 [59]

Answer:

-60

Step-by-step explanation:

If the worker is descending, he is going down. The change in his position could be marked on a graph by translating the original point down by 60 units. Aka -60 units.

8 0

3 years ago

What is the answer key to GO MATH 6grade page 393

Lina20 [59]

Answer:

This website is not an answer key website. You ask a question and we respond. Write your question and ill reply. Thanks for the points.

Step-by-step explanation:

7 0

3 years ago

Which statement best reflects the solution(s) of the equation?

Inessa [10]

x=2 is only solution while x=1 is extraneous solution

Option C is correct.

Step-by-step explanation:

We need to solve the equation $\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}$ and find values of x.

Solving:

Find the LCM of denominators x-1,x and x-1. The LCM is x(x-1)

Multiply the entire equation with x(x-1)

$\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}\\\frac{1}{x-1}*x(x-1)+\frac{2}{x}*x(x-1)=\frac{x}{x-1}*x(x-1)\\Cancelling\,\,out\,\,the\,\,same\,\,terms:\\x+2(x-1)=x^2\\x+2x-2=x^2\\3x-2=x^2\\x^2-3x+2=0$

Now, factoring the term:

$x^2-2x-x+2=0\\x(x-2)-1(x-2)=0\\(x-1)(x-2)=0\\x-1=0\,\,and\,\, x-2=0\\x=1\,\,and\,\, x=2$

The values of x are x=1 and x=2

Checking for extraneous roots:

Extraneous roots: The root that is the solution of the equation but when we put it in the equation the answer turns out not to be right.

If we put x=1 in the equation, $\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}$ the denominator becomes zero i.e

$\frac{1}{1-1}+\frac{2}{1}=\frac{1}{1-1}\\\frac{1}{0}+2=\frac{1}{0}$

which is not correct as in fraction anything divided by zero is undefined. So, x=1 is an extraneous solution.

If we put x=2 in the equation,

$\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}$

$\frac{1}{2-1}+\frac{2}{2}=\frac{2}{2-1}\\\frac{1}{1}+1=\frac{2}{1}\\1+1=2\\2=2$

So, x=2 is only solution while x=1 is extraneous solution

Option C is correct.

Keywords: Solving Equations and checking extraneous solution

Learn more about Solving Equations and checking extraneous solution at:

#learnwithBrainly

5 0

3 years ago

Gt6tys56ytujr7dsy6rtuhgjfyhjfvchfgjvcxfdcgfhvn jhmc dghvbdcjghb

Kazeer [188]

Answer:

It is 42=x

Step-by-step explanation:

bruh

5 0

2 years ago