Answer:
the dimensions that minimize the cost of the cylinder are R= 3.85 cm and L=12.88 cm
Step-by-step explanation:
since the volume of a cylinder is
V= π*R²*L → L =V/ (π*R²)
the cost function is
Cost = cost of side material * side area + cost of top and bottom material * top and bottom area
C = a* 2*π*R*L + b* 2*π*R²
replacing the value of L
C = a* 2*π*R* V/ (π*R²) + b* 2*π*R² = a* 2*V/R + b* 2*π*R²
then the optimal radius for minimum cost can be found when the derivative of the cost with respect to the radius equals 0 , then
dC/dR = -2*a*V/R² + 4*π*b*R = 0
4*π*b*R = 2*a*V/R²
R³ = a*V/(2*π*b)
R= ∛( a*V/(2*π*b))
replacing values
R= ∛( a*V/(2*π*b)) = ∛(0.03$/cm² * 600 cm³ /(2*π* 0.05$/cm²) )= 3.85 cm
then
L =V/ (π*R²) = 600 cm³/(π*(3.85 cm)²) = 12.88 cm
therefore the dimensions that minimize the cost of the cylinder are R= 3.85 cm and L=12.88 cm
Answer:
A. 45 in
Step-by-step explanation:
To find area you multiply length and width so you would multiply 9 and 10 but since it is a triangle you would divide by two
Hope this helps!
Note: I just noticed that you only have one negative sign. If you mean to put -9, change the sign to positive. If not, leave the answer.
Note the equal sign. what you do to one side, you do to the other. Isolate the x. First, multiply 3 to both sides
-x/3(3) = 9(3)
-x = 9(3)
-x = 27
Next, to isolate the x, divide -1 from both sides
-x/-1 = 27/-1
x = 27/-1
x = -27
-27 is your answer for x.
hope this helps
Answer:
theres no picture ill still answer if you put a picture or somthing of the triangle
Step-by-step explanation:
