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Westkost [7]
2 years ago
9

Help me with this!!!!!

Mathematics
1 answer:
myrzilka [38]2 years ago
6 0

Answer:

40

Step-by-step explanation:

The formula for a rhombuses area is (pq)/2. If we fill in the values, we get 80/2 = 40

Hope this helped! If this is incorrect, please tell me and I will fix it as soon as possible!

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What is the value of f(4) + f(7)
DochEvi [55]

Answer:

11

Step-by-step explanation:


7 0
3 years ago
Solve for x to the nearest 10th.<br> 410 = 1080(0.915)^x
Hunter-Best [27]

Answer:

410/1080=(0.915)^x

0.379=(0.915)^x

ln0. 379/ln0.915=x

X=10.903

4 0
3 years ago
I don’t get it it doesn’t make sense
san4es73 [151]

Answer:

Area of A = 32ft

Area of B = 36ft

Step-by-step explanation:

All you need to do to solve is multiply width * length * height.

If you do so,

Area of A = 3 * 2 * 5 1/3

= 6 * 16/3

= 32

Area of B = 6 * 4 * 1 1/2

= 24 * 3/2

= 36

Hope this helps!!

Let me know if I'm wrong or you need help in any other problem!!

7 0
3 years ago
Read 2 more answers
How do u do this in advanced math​
UNO [17]
Answer is d = 50.

Step by step. These are vertical angles so the (d + 70) will equal the opposite angle of 120.

Equation is d + 70 = 120.

Solve for d. Subtract 70 from both sides of the equal sign to solve for d.

d + 70 - 70 = 120 - 70
d = 50
4 0
1 year ago
Pixel goes shopping with one hundred dollars and ends up buying three different types of items: A, B, and C. The unit price of A
mixas84 [53]

Answer:

  • A - 16, B - 79, C - 5

Step-by-step explanation:

<u>Given</u>

  • A costs 5$
  • B costs  $0.25
  • C costs $0.05
  • A + B + C = 100
  • 5A + 0.25B + 0.05C = 100 ⇒ 100A + 5B + C = 2000

<u>Subtract the first equation from the second:</u>

  • 99A + 4B = 1900

<u>We have a restriction in numbers:</u>

  • 0 < A, B, C < 100

<u>Since 4B can be max 400, we get 99A > 1500  and 99A < 1900 so:</u>

  • A > 1500/99 > 15

and

  • A < 1900/99 < 19

A can be 16 or 18 as it should be even number to get B the whole number.

<u>If A = 16:</u>

  • 99*16 + 4B = 1900
  • 4B = 1900 - 1584
  • 4B = 316
  • B = 316/4 = 79

<u>If A = 18:</u>

  • 99*18 + 4B = 1900
  • 4B = 1900 - 1782
  • 4B = 118
  • B = 118/4 = 29.5, discarded as decimal

<u>So we get:</u>

  • A = 16, B = 79 and C = 100 - (16 + 79) = 5

<u>Let's proof the numbers:</u>

  • 16*5 + 79*0.25 + 5*0.05 = 100, confirmed

5 0
2 years ago
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