<h2>
Answer:</h2>
The expression that is equivalent to the given expression is:
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Step-by-step explanation:</h2>
Two expression are said to be equivalent if by some simplification i.e. by some multiplication or division it could be represented in the same manner.
Here we are given a expression as:
g^{-m} ÷ g^n i.e.
We know that:
Hence, we get:
Answer: (x^2)/25 + (16y^2)/375) = 1
Step-by-step explanation:
since foci are symetrically located on x-axis about origin, the equation of the ellipse must be of the following form:
(x^2)/(a^2) + (y^2)/(b^2) = 1, where a = semi-major axis, and b = semi-minor axis,
and: e = eccentricity = sqrt(a^2 - b^2)/a = 0.25; foci located at (+/- sqrt(a^2 - b^2),0) = (+/- 1.25,0)
---> sqrt(a^2 - b^2) = 1.25 ---> 1.25/a = 0.25 ---> a = 1.25/0.25 ---> a = 5; and sqrt(a^2 - b^2) = 1.25 = 5/4
---> a^2 - b^2 = (5/4)^2 = 25/16; or 5^2 - b^2 = 25/16 ---> 25 - b^2 = 25/16;
---> b^2 = 25 - (25/16) = 25[1 - 1/16] = 25(15)/16 = 375/16
---> (x^2)/25 + (y^2)/(375/16) = 1 ---> (x^2)/25 + (16y^2)/375) = 1
Hope this help...and correct it's been awhile..Let me know
Any geometric sequence can be expressed as:
a(n)=ar^(n-1), a=initial term, r=common ratio, n=term number
We are given that a(5)=1/16 and r=1/4 so we can say:
1/16=a(1/4)^(5-1)
1/16=a(1/4)^4
1/16=a/256
256/16=a
16=a
So the initial term is 16 so our formula is:
a(n)=16(1/4)^(n-1)
Put all of the numbers in order from least to greatest. 76, 89, 89, 93, 98. The number in the middle of this list is the median. The mediuan is 89.
Here the only limitation on the domain exists when the denominator is equal to zero, as division by zero has no meaning and is not "allowed" because of its meaninglessness. :)
Factor the denominator to find the excluded values of x...
3x^2+5x-12
3x^2+9x-4x-12
3x(x+3)-4(x+3)
(3x-4)(x+3)
So x CANNOT equal 4/3 or -3 (all other real values of x are part of the domain) so the domain is:
x=(-oo, -3),(-3, 4/3),(4/3, +oo)
