Answer: There are 
ways of doing this
Hi!
To solve this problem we can think in term of binary numbers. Let's start with an example:
n=5, A = {1, 2 ,3}, B = {4,5}
We can think of A as 11100, number 1 meaning "this element is in A" and number 0 meaning "this element is not in A"
And we can think of B as 00011.
Thinking like this, the empty set is 00000, and [n] =11111 (this is the case A=empty set, B=[n])
This representation is a 5 digit binary number. There are 
of these numbers. Each one of this is a possible selection of A and B. But there are repetitions: 11100 is the same selection as 00011. So we have to divide by two. The total number of ways of selecting A and B is the 
.
This can be easily generalized to n bits.
Ruby eats two slices of pie
Fraction generally represents a part of the whole. The number present in the upper side is called as numerator and the number present below is called as denominator. Fraction can also be represented as a decimal or percentage when required.
Fraction of pie Ruby ate = 1/5
Number of slices present in the pie = 10
numerical value of a fraction = fraction x total number
So, total number of slices of pie that Ruby ate = 10 x 1/5 = 2
Therefore, Ruby eats two slices of pie.
Ruby ate 1/5 of a pie and if there was 10 slices of pie, it implies Ruby eats two slices of pie.
To learn more about fraction refer here
brainly.com/question/11562149
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Answer:
To develop a molecular clock, you need to find which of the following?
a sequence of molecules
the rate at which changes occur in a type of molecule
how much total change has occurred in a type of molecule from two different species
how many molecules a species has
Step-by-step explanation:
To develop a molecular clock, you need to find which of the following?
a sequence of molecules
the rate at which changes occur in a type of molecule
how much total change has occurred in a type of molecule from two different species
how many molecules a species has
Answer:
3/10
Step-by-step explanation:
fouth grade students at Estrabook make up 0.3 percents of the students at school
The fraction is therefore equivalent to
= 3/10
