1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lana [24]
2 years ago
9

The local high school is hosting an ice cream social for new students. They record the ice cream choices of the students through

out the event. What is the probability that a person who chose vanilla ice cream is male? Vanilla Strawberry Chocolate Total Male 6 4 13 23 Female 8 9 4 21 Total 13 17 4 O A. O MN O B. 3 22 O c. OD. 6 23​

Mathematics
2 answers:
Masteriza [31]2 years ago
6 0

Answer:

6/23

Step-by-step explanation:

There are 6 males who want ice cream out of the 23 males that are there

4vir4ik [10]2 years ago
5 0

Answer:

The answer is 6 / 23

So, the probability that a person who choose vanilla ice cream is 6 / 23 .

You might be interested in
Find the area of the shaded region.
jolli1 [7]

Answer:

15x-36

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Suppose the scores on a test given to all juniors in a school district are normally distributed with a mean of 74 and a standard
ivann1987 [24]

Answer:

\mu -\sigma = 66 , \mu +\sigma = 82

\mu -2\sigma = 58 , \mu +2\sigma = 90

\mu -3\sigma = 50 , \mu +3\sigma = 98

And in the figure attached we see the limits with the percentages associated.

Step-by-step explanation:

For this case we know that the random variable of interest is the scores on a test given to all juniors in a school district follows a normal distribution with the following parameters:

X \sim N(\mu= 74, \sigma =8)

For this case we know from the empirical rule that within one deviation from the mean we have approximately 68.2% of the data, within 2 deviations from the mean we have 95% and within 3 deviation 99.7%

We can find the limits and we got:

\mu -\sigma = 66 , \mu +\sigma = 82

\mu -2\sigma = 58 , \mu +2\sigma = 90

\mu -3\sigma = 50 , \mu +3\sigma = 98

And in the figure attached we see the limits with the percentages associated.

7 0
4 years ago
Test 69,000 on hearing to for divisibility by 2 3 5 9 or 10
svetoff [14.1K]
Yes they are correct
7 0
4 years ago
Let A, B, C and D be sets. Prove that A \ B and C \ D are disjoint if and only if A ∩ C ⊆ B ∪ D
ANEK [815]

Step-by-step explanation:

We have to prove both implications of the affirmation.

1) Let's assume that A \ B and C \ D are disjoint, we have to prove that A ∩ C ⊆ B ∪ D.

We'll prove it by reducing to absurd.

Let's suppose that A ∩ C ⊄ B ∪ D. That means that there is an element x that belongs to A ∩ C but not to B ∪ D.

As x belongs to A ∩ C, x ∈ A and x ∈ C.

As x doesn't belong to B ∪ D, x ∉ B and x ∉ D.

With this, we can say that x ∈ A \ B and x ∈ C \ D.

Therefore, x ∈ (A \ B) ∩ (C \ D), absurd!

It's absurd because we were assuming that A \ B and C \ D were disjoint, therefore their intersection must be empty.

The absurd came from assuming that A ∩ C ⊄ B ∪ D.

That proves that A ∩ C ⊆ B ∪ D.

2) Let's assume that A ∩ C ⊆ B ∪ D, we have to prove that A \ B and C \ D are disjoint (i.e.  A \ B ∩ C \ D is empty)

We'll prove it again by reducing to absurd.

Let's suppose that  A \ B ∩ C \ D is not empty. That means there is an element x that belongs to  A \ B ∩ C \ D. Therefore, x ∈ A \ B and x ∈ C \ D.

As x ∈ A \ B, x belongs to A but x doesn't belong to B.  

As x ∈ C \ D, x belongs to C but x doesn't belong to D.

With this, we can say that x ∈ A ∩ C and x ∉ B ∪ D.

So, there is an element that belongs to A ∩ C but not to B∪D, absurd!

It's absurd because we were assuming that A ∩ C ⊆ B ∪ D, therefore every element of A ∩ C must belong to B ∪ D.

The absurd came from assuming that A \ B ∩ C \ D is not empty.

That proves that A \ B ∩ C \ D is empty, i.e. A \ B and C \ D are disjoint.

7 0
4 years ago
There were two trees growing from seeds in a backyard. One tree grew at a rate of 1//2 of a foot every 2 years. The other grew 4
Ann [662]

Answer:

The height between the two trees will be 1.67 feet.

Step-by-step explanation:

What you do is you take the 1/2 have and times it by 6 because it is every two years that the tree grows 1/2 of a foot. So it will be 3 feet. The other tree grew 4 inches in 3 years so it will be 16 inches you will then have to make the 16 inches into feet to get 1 1/3. You will then minus the 3 feet and the 1 1/3 to get 5/3 or 1.67 feet.

7 0
3 years ago
Other questions:
  • Which of the following ordered pairs is a solution to y = 2x?
    14·2 answers
  • A players options are defined and limited by rules, but how and when the player makes gameplay choices are affected by the game
    13·1 answer
  • Pls help I forgot how this works
    6·1 answer
  • 4.9 convert it fraction
    15·2 answers
  • What is the 8th term of the geometric sequence with this explicit formula ?
    7·1 answer
  • Upload the worksheet with your constructions below.
    11·1 answer
  • How many times longer I s on be mile that one foot
    9·1 answer
  • Given that these triangles are similar, which side corresponds to side GE?
    10·2 answers
  • I need help with this
    5·2 answers
  • Determine whether the given sequence could be geometric, arithmetic, or neither. If possible, identify either the common ratio o
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!